我有两个servlet,它们映射在web.xml
:
<url-pattern>/archiving/archive</url-pattern>
<url-pattern>/archiving/reportgenerator</url-pattern>
从servlet archive
我调用第二个servlet:
request.getRequestDispatcher("/reportgenerator").forward(request, response);
但有错误:
NOT_FOUND
RequestURI=/reportgenerator
似乎在网址中我们在“ / reportgenerator ”之前丢失了“ / archiving ”。
但如果我在reaquestDispatcher
中添加“ / archiving ”:
request.getRequestDispatcher("/archiving/reportgenerator").forward(request, response);
然后我收到此错误:
NOT_FOUND
RequestURI=/archiving/archiving/reportgenerator
为什么servlet在第二种情况下复制了“ / archiving ”路径,但是不要先粘贴它?
答案 0 :(得分:1)
更改此行
request.getRequestDispatcher("/archiving/reportgenerator").forward(request, response);
到
request.getRequestDispatcher("../archiving/reportgenerator").forward(request, response);
看看这是否有帮助。