Question

我希望使用LEFT JOIN查询从两个具有一对多关系的表中获取一些结果，但是根据“children”的数量来限制结果集。我有两个表格结构如下：

customers
id    name    ...
1     "bob"   ...
2     "jill"  ...

orders
id    customer_id    ...
100   1              ...
101   2              ...
102   1              ...

（表中的其余数据与此查询无关。）

我想要做的是获取所有客户ID及其订单ID，按客户排序，但仅限于已订购多个订单的客户。在此示例中，结果将是看起来像：

cust_id    order_id
1          100
1          102

我已经开始使用基本LEFT JOIN将订单ID与其客户配对，但无法弄清楚如何将所有未订购至少两次的客户排除在外。

SELECT 
    `customers`.`id` AS `cust_id`,
    `orders`.`id` AS `order_id`
FROM
    `customers`
LEFT JOIN `orders` ON
    `customers`.`id` = `orders`.`customer_id`
ORDER BY
    `cust_id`

谢谢大家。

Answer 1

一种方法是创建一个内联视图，该视图可以获得具有多个订单的客户以及内部联接。如果你不喜欢JOIN

，你也可以做IN或EXISTS

SELECT 
    `customers`.`id` AS `cust_id`,
    `orders`.`id` AS `order_id`
FROM
    `customers`
LEFT JOIN `orders` ON
    `customers`.`id` = `orders`.`customer_id`
INNER JOIN 
      (SELECT `customer_id `    
       FROM `orders`
       GROUP BY `customer_id`    
       HAVING COUNT(id) > 1) as `morethanone`
On
    `customer`.`id`  = `morethanone`.`custmor_id`
ORDER BY
    `cust_id`

Answer 2

首先，您不需要将联接留在外部，因为它与内部联接之间的唯一区别将包括没有订单的客户，并且您在结果中不需要它们，因为它们的数量较少比两个订单。

SELECT customers.id AS `cust_id`, orders.id AS `order_id`
FROM customers
     INNER JOIN orders ON `customers`.`id` = `orders`.`customer_id`
     INNER JOIN orders count_orders ON customers.id = count_orders.customer_id
GROUP BY count_orders.id, orders.id
HAVING count(count_orders.id) >= 2
ORDER BY `cust_id`

Answer 3

嘿，我觉得我有点慢，但无论如何我都会发布我的答案。它略有不同，但仍然有效。

SELECT `customers`.`id` AS `cust_id` , count( orders.id ) AS count_orders
FROM `customers`
JOIN `orders` ON `customers`.`id` = `orders`.`customer_id`
GROUP BY customers.id
HAVING count( orders.id ) >1
ORDER BY `cust_id`

Answer 4

如果您排除未订购的客户，则不需要LEFT JOIN，不是吗？

由于您需要结果集中的订单ID，因此需要先运行COUNT查询。

在SQL Server，2005 +中，CTE将执行计数查询的技巧，然后可以根据该计数查询生成所需的结果集：

WITH customerWithMoreThanOneOrder AS
(
    SELECT 
        `customers`.`id` AS `cust_id`
    FROM
        `customers`
    INNER JOIN `orders` ON
        `customers`.`id` = `orders`.`customer_id`
    GROUP BY 
        `customers`.`id`
    HAVING COUNT(0) > 1
)

SELECT 
    `customers`.`id` AS `cust_id`,
    `orders`.`id` AS `order_id`
FROM
    `customers`
INNER JOIN `orders` ON
    `customers`.`id` = `orders`.`customer_id`
WHERE `customers`.`id` IN (SELECT cust_id FROM customerWithMoreThanOneOrder)
ORDER BY
    `cust_id`

如果您使用的数据库不支持此结构，则只需将计数查询放在IN子查询的括号中，如下所示：

SELECT 
    `customers`.`id` AS `cust_id`,
    `orders`.`id` AS `order_id`
FROM
    `customers`
INNER JOIN `orders` ON
    `customers`.`id` = `orders`.`customer_id`
WHERE `customers`.`id` IN (SELECT 
                               `customers`.`id` AS `cust_id`
                           FROM
                               `customers`
                           INNER JOIN `orders` ON
                               `customers`.`id` = `orders`.`customer_id`
                           GROUP BY 
                               `customers`.`id`
                           HAVING COUNT(0) > 1)
ORDER BY
    `cust_id`

如果您有任何问题，请告诉我

Answer 5

替代其他答案，您可以使用IN子句。

SELECT 
    `customers`.`id` AS `cust_id`,
    `orders`.`id` AS `order_id`
FROM
    `customers`
LEFT JOIN `orders` ON
    `customers`.`id` = `orders`.`customer_id`
WHERE `customer_id` IN (SELECT `customer_id` FROM `orders` GROUP BY `customer_id` HAVING COUNT(*) > 1)
ORDER BY
    `cust_id`

如何通过count限制SQL LEFT JOIN查询的结果集

5 个答案: