Question

我使用SimpleXML通过RSS获取我的推文。我想在推文上点击链接。但我无法想象如何。我尝试了一些不起作用的东西。需要你的帮助。

这是我的代码;

<? 
$twitterRssFeedUrl =  "https://api.twitter.com/1/statuses/user_timeline.rss?screen_name=puzzletravel";
$twitterUsername = "puzzletravel";
$amountToShow = 5;

$twitterPosts = false;
$xml = @simplexml_load_file($twitterRssFeedUrl);
$reg_exUrl = "/(http|https|ftp|ftps)\:\/\/[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(\/\S*)?/";
$text = $xml;
if(is_object($xml)){
    //Rest of our code will be here
}else{
    die('cannot connect to twitter feed');
}

foreach($xml->channel->item as $twit){
    if(is_array($twitterPosts) && count($twitterPosts)==$amountToShow){
        break;
    }
     $d['title'] = stripslashes(htmlentities($twit->title,ENT_QUOTES,'UTF-8'));
    $description = stripslashes(htmlentities($twit->description,ENT_QUOTES,'UTF-8'));
    if(strtolower(substr($description,0,strlen($twitterUsername))) == strtolower($twitterUsername)){
        $description = substr($description,strlen($twitterUsername)+1);
    }
    $d['description'] = $description;
    $d['pubdate'] = strtotime($twit->pubDate);
    $d['guid'] = stripslashes(htmlentities($twit->guid,ENT_QUOTES,'UTF-8'));
    $d['link'] = stripslashes(htmlentities($twit->link,ENT_QUOTES,'UTF-8'));
    $twitterPosts[]=$d;
}

if(is_array($twitterPosts)){
    echo '<ul>';
    foreach($twitterPosts as $post){
        echo '<li><p>'.$post['description'].'</p><p class="date">'.date(' j F',$post['pubdate']).'</p></li>';
    }
    echo '</ul>';
}else{
    echo '<p>No Twitter posts have been made</p>';
}

?>

Answer 1

改变这个：

    echo '<li><p>'.$post['description'].'</p><p class="date">'.date(' j F',$post['pubdate']).'</p></li>';

到此：

    echo '<li><p><a href="'.$post['link'].'">'.$post['description'].'</p><p class="date">'.date(' j F',$post['pubdate']).'</a></p></li>';

Answer 2

我找到了解决问题的方法。以下是可能需要的人的解决方案。此解决方案将包含http，https的文本转换为可点击的URL。

<? 
$twitterRssFeedUrl =  "https://api.twitter.com/1/statuses/user_timeline.rss?screen_name=puzzletravel";
$twitterUsername = "puzzletravel";
$amountToShow = 7;

$twitterPosts = false;
$xml = @simplexml_load_file($twitterRssFeedUrl);
$reg_exUrl = "/(http|https)\:\/\/[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(\/\S*)?/";

if(is_object($xml)){
    //Rest of our code will be here
}else{
    die('Tweetler Alinamiyor');
}

foreach($xml->channel->item as $twit){
    if(is_array($twitterPosts) && count($twitterPosts)==$amountToShow){
        break;
    }
     $d['title'] = stripslashes(htmlentities($twit->title,ENT_QUOTES,'UTF-8'));
    $description = stripslashes(htmlentities($twit->description,ENT_QUOTES,'UTF-8'));
    if(strtolower(substr($description,0,strlen($twitterUsername))) == strtolower($twitterUsername)){
        $description = substr($description,strlen($twitterUsername)+1);
    }
    $d['description'] = $description;
    $d['pubdate'] = strtotime($twit->pubDate);
    $d['guid'] = stripslashes(htmlentities($twit->guid,ENT_QUOTES,'UTF-8'));
    $d['link'] = stripslashes(htmlentities($twit->link,ENT_QUOTES,'UTF-8'));
    $twitterPosts[]=$d;
}

if(is_array($twitterPosts)){
    echo '<ul>';
    foreach($twitterPosts as $post){

        if(preg_match($reg_exUrl, $post['description'], $url)) {
            $post['description']=preg_replace($reg_exUrl, "<a href={$url[0]}>{$url[0]}</a> ", $post['description']);
        }

        echo '<ul id="twitter_update_list">
              <li>
    <div id="tweet">'.$post['description'].'<a href="'.$post['link'].'">'.date(' j F',$post['pubdate']).'<br></a></li>';
    }
    echo '</ul>';
}else{
    echo '<p>Güncel Tweetler Oluşturulamadı Sayfayı Yenilemeyi Deneyin.</p></div>';
}

?>

如何在Twitter RSS上发布可点击的推文链接

2 个答案: