Question

我有一个查询，最后一天由Shaikh Farooque回答 Link of that question

现在我还有另外一个问题需要过滤那些位于相同cuisine_id下的foodjoint_id细节。 用户要提交lat long和cuisine_id我需要过滤那些FoodJoint

正如我告诉过你我已经在Lat Long搜索Food Joint现在正在运行我需要添加菜式过滤器。

正在运行的查询是

SELECT foodjoint_id,foodjoint_name,open_hours,cont_no,address_line,city, 
( 3959 * acos( cos( radians('".$userLatitude."') ) * 
   cos( radians( foodjoint_latitude) ) * cos( radians( foodjoint_longitude) - 
   radians('".$userLongitude."') ) + sin( radians('".$userLatitude."') ) * 
   sin( radians( foodjoint_latitude) ) ) ) AS distance,
 (SELECT AVG(customer_ratings) 
 FROM customer_review 
 WHERE foodjoint_id=provider_food_joints.foodjoint_id) AS customer_rating 
 FROM provider_food_joints 
 HAVING distance < '3' ORDER BY distance

我添加了它：

SELECT foodjoint_id FROM menu_item WHERE cuisine_id=''.$userGivenCuisineId.''

我很遗憾地说问题仍未解决

Answer 1

SELECT foodjoint_id,foodjoint_name,open_hours,cont_no,address_line,city, 
( 3959 * acos( cos( radians('".$userLatitude."') ) * 
   cos( radians( foodjoint_latitude) ) * cos( radians( foodjoint_longitude) - 
   radians('".$userLongitude."') ) + sin( radians('".$userLatitude."') ) * 
   sin( radians( foodjoint_latitude) ) ) ) AS distance,
(select AVG(customer_ratings) from customer_review where 
foodjoint_id=provider_food_joints.foodjoint_id) as customer_rating 
FROM provider_food_joints 
where  foodjoint_id in 
(SELECT foodjoint_id FROM menu_item WHERE cuisine_id='".$userGivenCuisineId."')
HAVING distance < '3' ORDER BY distance

Sql Sub查询需要添加两个查询

1 个答案: