我正在使用SQL Server - 2005 ...
ALTER Proc [dbo].[ExamResult] (@Course_Id varchar(100), @Semester varchar(10))
as
begin
declare @subjname varchar(100)
declare @subjects varchar(7000)
declare @subjectsselection varchar(7000)
declare @SumSelection varchar(7000)
declare @NoOfSubjects int
set @NoOfSubjects = 0
set @subjects = ''
set @subjectsselection = ''
set @SumSelection = ''
DECLARE subject_cursor CURSOR
FOR SELECT distinct Subject_Name FROM Exam_Result where course_id = @Course_Id And Semester = @Semester
OPEN subject_cursor
FETCH NEXT FROM subject_cursor
INTO @subjname
WHILE @@FETCH_STATUS = 0
BEGIN
set @subjects = @subjects + '[' + @subjname + '],'
set @subjectsselection = @subjectsselection + 'Sum(Isnull([' + @subjname + '],0)) As [' + @subjname + '],'
set @SumSelection = @SumSelection + 'Sum(Isnull([' + @subjname + '],0))+'
set @NoOfSubjects = @NoOfSubjects + 1
FETCH NEXT FROM subject_cursor
INTO @subjname
End
CLOSE subject_cursor;
DEALLOCATE subject_cursor;
select @subjects = LEFT(@subjects, LEN(@subjects) - 1)
select @subjectsselection = LEFT(@subjectsselection, LEN(@subjectsselection) - 1)
select @SumSelection = LEFT(@SumSelection, LEN(@SumSelection) - 1)
print @subjects
print @subjectsselection
print @SumSelection
declare @query nvarchar(4000)
set @query = 'select S.Enroll_Number, pvt.Student_Name, pvt.Course_Id, pvt.Semester, ' + @subjectsselection + ','
set @query = @query + 'Exam_Type,' + @SumSelection + ' As Grand_Total, '
set @query = @query + '(' + @SumSelection + ')' + '/' + convert(varchar(10),@NoOfSubjects) + ' As Avg'
set @query = @query + ' From '
set @query = @query + '(select Enroll_Number, Student_Name, Course_Id, Semester, Subject_Name, MarksObtained, Exam_Type from Exam_Result ) ps '
set @query = @query + ' pivot(sum(MarksObtained) for Subject_Name in (' + @subjects + ')) as pvt'
set @query = @query + ' inner join Stud_Info S on S.Enroll_Number = pvt.Enroll_Number '
set @query = @query + ' where pvt.Course_Id = ''' + @Course_Id + ''' and pvt.Semester = ''' + @Semester + ''''
set @query = @query + ' group by S.Enroll_Number, pvt.Student_Name, pvt.Course_Id, pvt.Semester, Exam_Type'
print @query
exec sp_executesql @query
end
Exam_Result表:
CREATE TABLE [dbo].[Exam_Result](
[Result_Id] [int] IDENTITY(1,1) NOT NULL,
[Enroll_Number] [varchar](50) NULL,
[Student_Name] [varchar](100) NULL,
[Course_Id] [varchar](50) NULL,
[Semester] [varchar](50) NULL,
[Subject_Id] [varchar](50) NULL,
[Subject_Name] [varchar](50) NULL,
[MarksObtained] [Varchar](10) NULL,
[Exam_Type] [varchar](50) NULL)
示例数据查询 ...
INSERT into Exam_Result VALUES('11147','Mr.Mack28','CIV','1','PS1','ps1','60','Final')
INSERT into Exam_Result VALUES('11147','Mr.Mack28','CIV','3','PS1','ps1','70','Final')
INSERT into Exam_Result VALUES('11147','Mr.Mack28','CIV','3','PS1','ps1','80','Final')
INSERT into Exam_Result VALUES('11147','Mr.Mack28','CIV','3','PS1','ps1','20','Internal')
INSERT into Exam_Result VALUES('11147','Mr.Mack28','CIV','3','PS1','ps1','22','Internal')
Student_Info表:我只是用于检索 Student_Information ,例如Enroll_Number ......
CREATE TABLE [dbo].[Stud_Info](
[Enroll_Number] [varchar](20) NOT NULL,
[Student_Name] [varchar](20) NULL,
[Course_Type] [varchar](20) NULL,
[Course_Id] [varchar](20) NULL,
[Semester] [varchar](20) NULL,
[Password] [varchar](20) NULL,
[Gender] [varchar](6) NULL,
[City] [varchar](15) NULL,
[Mobile_Number] [varchar](10) NULL)
它给我这样的错误......
Msg 8117,Level 16,State 1,Line 1
操作数数据类型varchar对sum运算符无效。
Rahul :根据你的回答我更新了这样但它仍然给出了错误......
set @query = @query + ' pivot(sum(cast(MarksObtained as int)) for Subject_Name in (' + @subjects + ')) as pvt'
我认为它会出错,因为我使用MarksObtained
列(as varchar(10)
)... plz给我一个建议我如何将varchar
转换为int
所以可以完成总MarksObtained
的总和。
答案 0 :(得分:3)
您可以这样转换:
SUM (CONVERT(int,<your varchar column>))
如果您的varchar列实际上包含数值,这将有效。否则,您可以尝试使用cast
函数进行投射,例如:
sum(cast(varchar_column as int))
修改
创建了一个只有2列(name和marksobtained)的样本表,两者都是varchar(10)
类型,并向其中插入了一些数据。所以我的select *
看起来像
name marksobtained
Mr. Anil 30
Mr. sunil 70
Mr. patel 70
总结了像
这样的标记select SUM(cast(marksobtained as int)) as 'totalmarksobtained' from sampletab
返回了170
。
@subjects
有什么价值?发布一些样本。
答案 1 :(得分:0)
你可以使用&#34; cast&#34;在您的查询中
示例:
select sum(cast(Enter_your_field_name as int)) from Table_name
希望它适合你。