Question

我有以下不返回结果的查询：

1. SELECT *
2. FROM wp_postmeta pm
3. LEFT JOIN wp_posts p ON (p.ID = pm.post_id)
4. LEFT JOIN wp_term_relationships tr ON (p.ID = tr.object_id)
5. LEFT JOIN wp_term_taxonomy tt ON (tr.term_taxonomy_id = tt.term_taxonomy_id)
6. WHERE p.post_status = 'publish' 
7. AND p.post_type = 'post' 
8. AND p.post_date < NOW()+INTERVAL 1 DAY 
9. AND tt.taxonomy = 'category' 
10. AND tt.term_id IN(3)
11. AND (pm.meta_key = 'EndDate' AND pm.meta_value > DATE_ADD(NOW(), INTERVAL 3 HOUR)) 
12. AND (pm.meta_key = 'NumPrizes' AND pm.meta_value > 1)
13. GROUP BY ID
14. ORDER BY p.ID DESC

问题出现是因为第11行和第12行。我可以删除其中一个并获得结果，但我需要两个才能得到我想要的结果。

我想要的是获得pm.meta_key EndDate大于今天且pm.meta_key NumPrizes大于0的结果。

想法是输出数据库中的奖品总数。

数据库是由wordpress构建的，所以我无法改变它。它的工作方式是meta_key有一个值，它是字段的名称，meta_value是meta_key的实际值。

wp_postmeta表的示例：

meta_id     post_id    meta_key   meta_value
1           45         EndDate    2012-01-01    <- too old
2           45         NumPrizes  5             <- since too old, don't count
3           76         EndDate    2012-07-03    <- valid date but...
4           76         NumPrizes  1             <- only 1 prize so don't count
5           90         EndDate    2012-06-02    <- valid date and
6           90         NumPrizes  4             <- more than one prize so count it
7           192        EndDate    2012-09-01    <- valid date and
8           192        NumPrizes  9             <- more than one prize so count it

预期输出：奖品数量为13.（4 + 9 = 13）。

有人能指出我正确的方向吗？

Answer 1

当然，单个列一次不能获取两个不同的值：

11. AND pm.meta_key = 'EndDate'      <<-- big error: column can't take two
12. AND pm.meta_key = 'NumPrizes'    <<--      differents values at a time

您应该规范化表格和/或编写正确的查询：

1. SELECT *
2. FROM wp_postmeta pm
3. LEFT JOIN wp_posts p ON (p.ID = pm.post_id)
4. LEFT JOIN wp_term_relationships tr ON (p.ID = tr.object_id)
5. LEFT JOIN wp_term_taxonomy tt ON (tr.term_taxonomy_id = tt.term_taxonomy_id)
6. WHERE p.post_status = 'publish' 
7. AND p.post_type = 'post' 
8. AND p.post_date < NOW()+INTERVAL 1 DAY 
9. AND tt.taxonomy = 'category' 
10. AND tt.term_id IN(3)
11. AND (pm.meta_key = 'EndDate' AND pm.meta_value > DATE_ADD(NOW(), INTERVAL 3 HOUR)) 
12. AND exists (
          select 1 from wp_postmeta pm2 where
          pm2.post_id  = pm.post_id and
          pm2.meta_key = 'NumPrizes' AND pm2.meta_value > 1
    )
13. GROUP BY ID
14. ORDER BY p.ID DESC

<强> EDITED

Jonathan，我不知道您的预期结果，因为您在讨论单个标量结果（数字13），但在您的查询中，您将主表与其他表连接。我希望我在这里写的代码对你有帮助，但你应该根据你的具体情况进行调整。

1. SELECT *, sum( __your_prizes_agrregation__ )
2. FROM wp_postmeta pm
3. LEFT JOIN wp_posts p ON (p.ID = pm.post_id)
4. LEFT JOIN wp_term_relationships tr ON (p.ID = tr.object_id)
5. LEFT JOIN wp_term_taxonomy tt ON (tr.term_taxonomy_id = tt.term_taxonomy_id)
6. WHERE p.post_status = 'publish' 
7. AND p.post_type = 'post' 
8. AND p.post_date < NOW()+INTERVAL 1 DAY 
9. AND tt.taxonomy = 'category' 
10. AND tt.term_id IN(3)
11. AND exists (
          select 1 from wp_postmeta pm2 where
          pm2.post_id  = pm.post_id and
          pm2.meta_key = 'EndDate' AND 
          pm2.meta_value > DATE_ADD(NOW(), INTERVAL 3 HOUR)
    )
12. AND exists (
          select 1 from wp_postmeta pm2 where
          pm2.post_id  = pm.post_id and
          pm2.meta_key = 'NumPrizes' AND pm2.meta_value > 1
    )
13. GROUP BY ID
14. ORDER BY p.ID DESC

MYSQL查询两次相同的字段

1 个答案: