如何在selenium webdriver(firefox)中打开新选项卡上的链接?
<a href='/test' id='test'>Link</a>
driver.find_element_by_id('test').click()
答案 0 :(得分:1)
目前看来你最好的选择是在页面中注入一个锚标签。你需要将它改编为python,但它应该相对简单:https://stackoverflow.com/a/9122450/39843
答案 1 :(得分:1)
package com.crm.qa.BaseTest;
import java.awt.AWTException;
import java.awt.Robot;
import java.awt.event.KeyEvent;
import java.util.ArrayList;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.chrome.ChromeDriver;
public class NewTabChrome {
public static void main(String[] args) throws AWTException {
System.setProperty("webdriver.chrome.driver",
"C:/Users/sunil/Downloads/chromedriver_win32 (2)/chromedriver.exe");
WebDriver driver = new ChromeDriver();//open browser
driver.manage().window().maximize();//browser maximize
driver.get("http://www.google.com");//open google
//open new tab
for(int i = 0; i<=1;i++){
Robot rob = new Robot();
rob.keyPress(KeyEvent.VK_CONTROL);
rob.keyPress(KeyEvent.VK_T);
rob.keyRelease(KeyEvent.VK_CONTROL);
rob.keyRelease(KeyEvent.VK_T);
ArrayList<String> tabs1 = new ArrayList<String> (driver.getWindowHandles());
//Switch to new tab
driver.switchTo().window((String) tabs1.get(i));
}
//open facebook
driver.get("http://facebook.com");
driver.quit();
}
}