想知道为什么一次点击不加载,但是两次................................. ................................?
<input id="btnPaymentAdd" type="button" value="Add Payment Info" />
</p>
<div id="paymentSection"></div>
<br />
....
$("#btnPaymentAdd").click(function () {
$("#paymentSection").load('/Donation/AddPaymentInfo');
$("#paymentSection").show('slow');
});
....
public ActionResult AddPaymentInfo()
{
var vModel = new PaymentViewModel();
vModel.Payment = new Payments();
vModel.PaymentType = new WCCDentalApp.Models.PaymentType();
ViewBag.PaymentTypes = new SelectList(dbEntities.PaymentTypes.OrderBy(pt => pt.PaymentTypeID),
"PaymentTypeID", "PaymentType1", vModel.Payment.PaymentTypeID);
return PartialView("PaymentPView", vModel);
}
答案 0 :(得分:2)
您需要在页面加载后绑定.show()
函数...
$("#btnPaymentAdd").click(function(){
$("#paymentSection").load('/Donation/AddPaymentInfo', function(){
$(this).show('slow');
});
});
或者您可以使用.get()
,如下所示:
$("#btnPaymentAdd").click(function(){
$.get('/Donation/AddPaymentInfo', function(data){
$("#paymentSection").html(data).show('slow');
});
});
否则,您拥有它的方式就是在不等待页面加载的情况下执行.show()
,这会使您认为点击它两次就可以了。