Question

我一直收到错误：

赋值使用指针生成整数而不使用强制转换

尝试使用以下命令编译我的哈希表ADT时：

gcc hash_NEW.c -c

在1个函数中遇到错误较大的.c文件。感谢您的帮助

错误1出现在此处（index = table-＆gt; hash_func;）

void insert_hash(Phash_table table, char *key, void *data){
    Phash_entry new;   //pointer to a new node of type hash_entry
    int index;

    new = (Phash_entry)malloc(sizeof(hash_entry));
    new->key = (char *)malloc(sizeof(char)*strlen(key));  //creates the key array based on the length of the string-based key
    new->data = data;              //stores the user's data into the node
    strcpy(new->key,key);          //copies the key into the node

                                   //calling the hash function in the user's program
    index = table->hash_func;      //index will hold the hash table value for where the new 
    table->buckets[index] = new;   //Assigns the pointer at the index value to the new node
    table->total++;                //increment the total (total # of buckets)
}

HEADER FILE的部分：

typedef struct hash_table_ {
    hash_entry **buckets;           //Pointer to a pointer to a Linked List of type hash_entry
    int (*hash_func)(char *);
    int (*cmp_func)(void *, void *);
    int size;
    void **sorted_array;      //Array used to sort each hash entry
    int index;//=0
    int total; //=0
    int sort_num; //=0  
} hash_table, *Phash_table;

Answer 1

查看类型定义，您可以看到Phash_table是指向结构的指针，该结构的字段hash_func是一个函数，它接受char *并返回int

很可能你想要：

 index = table->hash_func(key);

因为它正在尝试将“指向函数的指针”分配给“int”，这非常无法满足您的需求。

无法编译哈希表ADT - C.

1 个答案: