Question

我有一个我正在调用的方法但是，对于较新版本的Android，它会失败。显然，这是由于缺乏线程。我的方法是向我的服务器发送一条消息。这是代码（无线程）

public String sendMessage(String username, Editable message){
        BufferedReader in = null;
        String data = null;

        try{
            DefaultHttpClient client = new DefaultHttpClient();
            URI website = new URI("http://abc.com/user_send.php?username="+username+"&message="+message);

            HttpPost post_request = new HttpPost();
            post_request.setURI(website);


            HttpGet request = new HttpGet();

            request.setURI(website);
            //executing actual request
            HttpResponse response = client.execute(request);

            in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
            StringBuffer sb = new StringBuffer("");
            String l = "";
            String nl = System.getProperty("line.separator");
            while ((l = in.readLine()) != null) {
                sb.append(l);

            }
            in.close();
            data = sb.toString();
            return data;
        }catch (Exception e){
            return "ERROR";
        }
    }

现在，只是试图围绕它：

    public String sendMessage(String username, Editable message){
        BufferedReader in = null;
        String data = null;
Thread sendThread = new Thread(){
        try{
            DefaultHttpClient client = new DefaultHttpClient();
            URI website = new URI("http://thenjtechguy.com/njit/gds/user_send.php?username="+username+"&message="+message);

            HttpPost post_request = new HttpPost();
            post_request.setURI(website);


            HttpGet request = new HttpGet();

            request.setURI(website);
            //executing actual request
            HttpResponse response = client.execute(request);

            in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
            StringBuffer sb = new StringBuffer("");
            String l = "";
            String nl = System.getProperty("line.separator");
            while ((l = in.readLine()) != null) {
                sb.append(l);

            }
            in.close();
            data = sb.toString();
            return data;
        }catch (Exception e){
            return "ERROR";
        }
} sendThread.start();   
}

但这不起作用。我究竟做错了什么？另外，如果你注意到我违反了关于HttpClient的任何基本规则，请告诉我。

Answer 1

您的实现不正确 - 您没有覆盖run（）方法

class SendThread extends Thread {
   public void run(){
        //add your implementation here
   }
}

牵开线程

SendThread sendThread  = new SendThread();
sendThread.start();

Answer 2

更好地领导并使用AsyncTask概念。

AsyncTask可以正确，轻松地使用UI线程。此类允许执行后台操作并在UI线程上发布结果，而无需操作线程和/或处理程序。有关示例实现，请参阅此LINK

在android中创建线程无法正常工作

2 个答案: