Question

我需要阅读一个xml，我没有找到另一种方法来阅读它，我刚刚编辑了$ movie这个，我得到了这个错误信息：

Warning: file_get_contents(http://news.google.com.mx/news?hl=es&gl=mx&q=harry potter&bav=on.2,or.r_gc.r_pw.r_cp.r_qf.,cf.osb&um=1&ie=UTF-8&output=rss) [function.file-get-contents]: failed to open stream: HTTP request failed! HTTP/1.0 400 Bad Request

我收到此错误，这是我的代码，错误是在网址中有人可以帮助，如何解决？

$url = 
$data = file_get_contents('http://news.google.com.mx/news?hl=es&gl=mx&q='.$movie.'&bav=on.2,or.r_gc.r_pw.r_cp.r_qf.,cf.osb&um=1&ie=UTF-8&output=rss');

$xml = new SimpleXMLElement($data);
$channel = array();
$channel['title'] = $xml->channel->title;

foreach ($xml->channel->item as $item)
{

    //echo $article['title'] = $item->title;
    //echo $article['link'] = $item->link;
    echo $article['pubDate'] = $item->pubDate;
    echo $article['description'] = (string) trim($item->description);

}

Answer 1

如果你urlencode()有网址参数（例如$movie），它应该按预期工作。

示例：

$data = file_get_contents('http://news.google.com.mx/news?hl=es&gl=mx&q='. urlencode($movie) .'&bav=on.2,or.r_gc.r_pw.r_cp.r_qf.,cf.osb&um=1&ie=UTF-8&output=rss')

Answer 2

您需要在urlencode中包含$movie。我还添加了一个内容类型标题，以便您可以指定该Feed中使用的UTF-8编码，并为非英语字符正确呈现文本。

<?php

header('Content-Type:text/html;charset=utf-8');

$movie = 'harry potter';
$url = 
$data = file_get_contents('http://news.google.com.mx/news?hl=es&gl=mx&q='.urlencode($movie).'&bav=on.2,or.r_gc.r_pw.r_cp.r_qf.,cf.osb&um=1&ie=UTF-8&output=rss');

$xml = new SimpleXMLElement($data);
$channel = array();
$channel['title'] = $xml->channel->title;

foreach ($xml->channel->item as $item)
{
    //echo $article['title'] = $item->title;
    //echo $article['link'] = $item->link;
    echo $article['pubDate'] = $item->pubDate;
    echo $article['description'] = (string) trim($item->description);
}

?>

从谷歌新闻中读取xml时出错警告：file_get_contents

2 个答案: