Question

现在我有这样的控制器方法：

     def modelv
    @model = Model.find(:all, :conditions => { :MOD_MFA_ID => params[:man]}) 
    @ct = CountryDesignation.find(:all, :conditions => { :CDS_ID => "110000002"})
    @destext = DesText.find(:all, :conditions => { :TEX_ID => "388555"})
    respond_to do |format|
      format.html # show.html.erb
      format.xml  { render :xml => @model }
    end
  end

但我希望它看起来像这样：

 def modelv
    @model = Model.find(:all, :conditions => { :MOD_MFA_ID => params[:man]}) 
    @ct = CountryDesignation.find(:all, :conditions => { :CDS_ID => @model.MOD_CDS_ID})
    @destext = DesText.find(:all, :conditions => { :TEX_ID => @ct.CDS_TEX_ID})
    respond_to do |format|
      format.html # show.html.erb
      format.xml  { render :xml => @model }
    end
  end

但我的模型结构是：

COUNTRY_DESIGNATIONS has_many MODELS

DES_TEXTS has_many COUNTRY_DESIGNATIONS

制造商有很多型号

因此，如果我选择@model - 它是数组，如果选择@ct - 它的数组（对于每个模型），如果选择@destext - 它是数组。如何正确选择这个。以及如何在视图中显示这个？现在我的观点看起来像这样：

%p#notice= notice

%h3
  - @model.each do |model| 
    %tr
      %p
        mod_id
        %td= model.MOD_ID
        name
        -#%td= model.country_designations.des_texts.TEX_TEXT
      = link_to 'Show model', model
= link_to 'Back', manufacturers_path

我看起来不会这样：

%p#notice= notice

%h3
  - @model.each do |model| 
    %tr
      %p
        mod_id
        %td= model.MOD_ID
        name
        %td= @destext.TEX_TEXT
      = link_to 'Show model', model

= link_to 'Back', manufacturers_path

Answer 1

如果MODELS属于COUNTRY_DESIGNATIONS且COUNTRY_DESIGNATIONS属于DES_TEXTS，那么find应该只返回一个结果。然后你不需要找到（：all，...），你需要

@model = Model.find(:first, :conditions => { :MOD_MFA_ID => params[:man]}) 
@ct = CountryDesignation.find(:first, :conditions => { :CDS_ID => "110000002"})
@destext = DesText.find(:first, :conditions => { :TEX_ID => "388555"})

如何在rails控制器中选择？

1 个答案: