我有一个HTML主页,它使用的是jQuery mobile的UI。在HTML页面的某个地方,我有一个类似于投票表单的表单:
<form name = "vote" action = "logicDB.php" method = "post">
<center>
<h3>Watch our videos above and share your opinion which manufacturer produces the best sport sedans</h3>
<fieldset style = "width:60%;">
<legend>Choose a car:</legend>
<input type = "radio" name = "rc1" id = "radio-choice-1" value = "Audi"/>
<input type = "radio" name = "rc1" id = "radio-choice-2" value = "BMW"/>
<input type = "radio" name = "rc1" id = "radio-choice-3" value = "Mercedes"/>
</fieldset>
<input value = "SUBMIT" type = "submit" />
</center>
</form>
表单的action参数调用我的php文件,该文件具有以下逻辑:
<?php
$connection = mysql_connect("localhost","root","myPassword");
if(!$connection){ die('Could not connect: ' . mysql_error()); }
mysql_select_db("mydatabase", $connection);
if ($_POST['rc1'] == 'Audi')
{
mysql_query("
UPDATE carvote
SET votes = votes + 1
WHERE Brands = 'Audi'
",$connection);
echo "success Audi within if";
}
if ($_POST['rc1'] == 'BMW')
{
mysql_query("
UPDATE carvote
SET votes = votes + 1
WHERE Brands = 'BMW'
",$connection);
echo "success BMW within if";
}
if ($_POST['rc1'] == 'Mercedes')
{
mysql_query("
UPDATE carvote
SET votes = votes + 1
WHERE Brands = 'Mercedes'
",$connection);
echo "success Mercedes within if";
}
mysql_close($connection);
?>
我在我的WAMP localhost服务器上创建了一个数据库,这个php代码正在写入数据库,具体取决于从表单中选择和提交的无线电选项。从未达到过PHP中的这些回声。
问题在于,当我点击提交时,我会看到一个白色屏幕&#34; undefined&#34;在左上角,之后没有任何内容写入数据库。我发现如果我从html主页面中删除调用顶部jQuery mobile的行 一切正常,数据写入数据库(到达php中的回声)。 似乎jQuery mobile与我的php代码不兼容。我该怎么解决这个问题? 提前谢谢!
更新(我做到了): 以下是我在表单中所做的更改:
<form id = "ContactForm" onsubmit="return submitForm();">
与数据库的php文件保持不变。除此之外,我还添加了一个Ajax代码:
function submitForm()
{
$.ajax({type:'POST', url: 'logicDB.php', data:$('#ContactForm').serialize(), success: function(response)
{
$('#ContactForm').find('.form_result').html(response);
}});
return false;
}
总结一下:jQuery Mobile页面(带有data-role =&#34; div&#34;的div中的页面)只能通过AJAX提交。它不会起作用。 我会将主题更改为我的问题,以便更多人可以访问它。
答案 0 :(得分:6)
我复制了您的代码并插入了jquery mobile,在进行了一些小的更改后,我发布了数据。我通过echo命令运行它,而不是DB插入。
看看以下内容:
调用Jquery Mobile:
<!DOCTYPE html>
<html>
<head>
<title>My Page</title>
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="http://code.jquery.com/mobile/1.1.0/jquery.mobile-1.1.0.min.css" />
<script src="http://code.jquery.com/jquery-1.7.1.min.js"></script>
<script src="http://code.jquery.com/mobile/1.1.0/jquery.mobile-1.1.0.min.js"></script>
</head>
index.php页面的其余部分:
<div data-role="page">
<center>
<h3>Watch our videos above and share your opinion which manufacturer produces the best sport sedans</h3>
<form name="vote" action="logicDB.php" method="post" data-ajax="false">
<fieldset style = "width:60%;" data-role="controlgroup">
<legend>Choose a car:</legend>
<input type = "radio" name="rc1" id = "radio-choice-1" value = "Audi"/>
<label for="radio-choice-1">Audi</label>
<input type = "radio" name="rc1" id = "radio-choice-2" value = "BMW"/>
<label for="radio-choice-2">BMW</label>
<input type = "radio" name="rc1" id = "radio-choice-3" value = "Mercedes"/>
<label for="radio-choice-3">Mercedes</label>
</fieldset>
<input value = "SUBMIT" type = "submit" />
</form>
</center>
最后是logicDB.php
if ($_POST['rc1'] == 'Audi') {
echo "Audi <br>";
}
if ($_POST['rc1'] == 'BMW') {
echo "BMW <br>";
}
if ($_POST['rc1'] == 'Mercedes') {
echo "Mercedes <br>";
}
主要变化是
<fieldset style = "width:60%;" data-role="controlgroup">
和我之前提到的data-ajax="false"
。
看看它是否适合你。