Question

我有一组具有特定结构的文件：

COMPANY_DE-实际 - 内容 - 的 - 文件-RGB-ENG.pdf

故障：

公司 - ＆gt;公司名称，已修复
DE - ＆gt;办公地点，固定选项：'_DE'，'_ BE'或不存在非位置相关文件（如果存在，前面总是以下划线和公司名称开头）
实际内容文件，用短划线粘合的字符串
RGB - ＆gt; Colormode，固定选项：'RGB'，'CMYK'，'PMS'或缺少非颜色相关文件
ENG - ＆gt;文件语言，固定选项：“GER”，“ENG”或非文本相关文件不存在
pdf - ＆gt;扩展名，可以是任何

在最好的情况下，我的结果将是一个带有命名键的上述信息的数组，但不知道从哪里开始。

非常感谢帮助！

谢谢， Knal

很抱歉非常清楚，但文件名中始终存在一些变量： - DE - ＆gt;固定选项：'_ DE'，'_ BE'或缺席 - RGB - ＆gt; Colormode，固定选项：'RGB'，'CMYK'，'PMS'或缺席 - ENG - ＆gt;文件语言，固定选项：'GER'，'ENG'或缺席

Answer 1

尝试

$string = "COMPANY_DE-Actual-Contents-of-File-RGB-ENG.pdf";
$array = preg_split('/[-_\.]/', $string);

$len = count($array);
$struct = array($array[0], $array[1], '', $array[$len-3], $array[$len-2], $array[$len-1]);
unset($array[0], $array[1], $array[$len-3], $array[$len-2], $array[$len-1]);
$struct[2] = implode('-', $array);
var_dump($struct);

-

array
  0 => string 'COMPANY' (length=7)
  1 => string 'DE' (length=2)
  2 => string 'Actual-Contents-of-File' (length=23)
  3 => string 'RGB' (length=3)
  4 => string 'ENG' (length=3)
  5 => string 'pdf' (length=3)

Answer 2

如果可能的话，尽量不要使用正则表达式，或者保持它们尽可能简单。

$text = "COMPANY_DE-Actual-Contents-of-File-RGB-ENG.pdf";
$options_location = array('DE','BE');
$options_color = array('RGB','CMYK','PMS');
$options_language = array('ENG','GER');

//Does it have multiple such lines? In that case this:
$lines = explode("\n",$text);
//Then loop over this with a foreach, doing the following for each line:

$parts = preg_split('/[-_\.]/', $line);
$data = array(); //result array
$data['company'] = array_shift($parts); //The first element is always the company
$data['filetype'] = array_pop($parts); //The last bit is always the file type
foreach($parts as $part) { //we'll have to test each of the remaining ones for what it is
    if(in_array($part,$options_location))
        $data['location'] = $part;
    elseif(in_array($part,$options_color))
        $data['color'] = $part;
    elseif(in_array($part,$options_language))
        $data['lang'] = $part;
    else
        $data['content'] = isset($data['content']) ? $data['content'].' '.$part : $part; //Wasn't any of the others so attach it to the content
}

这也更容易理解，而不必弄清楚正则表达式到底在做什么。

请注意，这假定内容的任何部分都不能是为位置，颜色或语言保留的单词之一。如果在内容中可能出现这些情况，则必须添加isset($data['location'])之类的条件以检查是否已找到其他位置，如果是，则将正确的位置添加到内容而不是将其存储为位置

Answer 3

类似的东西：

preg_match('#^([^_]+)(_[^-]+)?-([\w-]+)-(\w+)-(\w+)(\.\w+)$#i', 'COMPANY_DE-Actual-Contents-of-File-RGB-ENG.pdf', $m);

preg_match('#^([^_]+)(_[^-]+)?-([\w-]+)-(\w+)[_-]([^_]+)(\.\w+)$#i', 'COMPANY_DE-Actual-Contents-of-File-RGB-ENG.pdf', $m); // for both '_' and '-'

preg_match('#^(\p{Lu}+)(-\p{Lu}+)?-([\w]+)(\-(\p{Lu}+))?(\-(\p{Lu}+))?(\.\w+)$#', 'COMPANY-NL-Actual_Contents_of_File-RGB-ENG.pdf', $m); // if filename parts divider is strictly '-'

var_dump($m);

在最后一个变体中，我们询问是否没有国家代码（-NL）它将为NULL。但是使用颜色和语言代码并非如此。亲自试试吧，你会弄清楚它是如何运作的！

Answer 4

怎么样：

$files = array(
    'COMPANY_DE-Actual-Contents-of-File-RGB-ENG.pdf',
    'COMPANY_BE-Actual-Contents-of-File-CMYK-ENG.pdf',
    'COMPANY_DE-Actual-Contents-of-File-PMS-GER.doc',
    'COMPANY-Actual-Contents-of-File-PMS-GER.doc',
    'COMPANY-Actual-Contents-of-File-GER.doc',
    'COMPANY-Actual-Contents-of-File.doc',
);

foreach($files as $file) {
    preg_match('/^(?<COMPANY>.*?)_?(?<LOCATION>DE|BE)?-(?<CONTENT>.*?)-?(?<COLOR>RGB|CMYK|PMS)?-?(?<LANG>ENG|GER)?\.(?<EXT>[^.]+)$/', $file, $m);
    echo "\nfile=$file\n";
    echo "COMPANY: ",$m['COMPANY'],"\n";
    echo "LOCATION: ",$m['LOCATION'],"\n";
    echo "CONTENT: ",$m['CONTENT'],"\n";
    echo "COLOR: ",$m['COLOR'],"\n";
    echo "LANG: ",$m['LANG'],"\n";
    echo "EXT: ",$m['EXT'],"\n";
}

<强>输出：

file=COMPANY_DE-Actual-Contents-of-File-RGB-ENG.pdf
COMPANY: COMPANY
LOCATION: DE
CONTENT: Actual-Contents-of-File
COLOR: RGB
LANG: ENG
EXT: pdf

file=COMPANY_BE-Actual-Contents-of-File-CMYK-ENG.pdf
COMPANY: COMPANY
LOCATION: BE
CONTENT: Actual-Contents-of-File
COLOR: CMYK
LANG: ENG
EXT: pdf

file=COMPANY_DE-Actual-Contents-of-File-PMS-GER.doc
COMPANY: COMPANY
LOCATION: DE
CONTENT: Actual-Contents-of-File
COLOR: PMS
LANG: GER
EXT: doc

file=COMPANY-Actual-Contents-of-File-PMS-GER.doc
COMPANY: COMPANY
LOCATION:
CONTENT: Actual-Contents-of-File
COLOR: PMS
LANG: GER
EXT: doc

file=COMPANY-Actual-Contents-of-File-GER.doc
COMPANY: COMPANY
LOCATION:
CONTENT: Actual-Contents-of-File
COLOR:
LANG: GER
EXT: doc

file=COMPANY-Actual-Contents-of-File.doc
COMPANY: COMPANY
LOCATION:
CONTENT: Actual-Contents-of-File
COLOR:
LANG:
EXT: doc

Answer 5

受到@Armatus的启发，我构建了以下似乎是故障安全的：

$string = "COMPANY_DE-Actual-Contents+of-File-RGB-ENG.pdf";
$options_location = array('DE','BE');
$options_color = array('RGB','CMYK','PMS');
$options_language = array('ENG','GER');
$parts = preg_split( '/[\.\-\_]/', $string, NULL, PREG_SPLIT_NO_EMPTY );

$data = array();
$data['company'] = array_shift($parts);
$data['filetype'] = array_pop($parts);

if( in_array( $parts[0], $options_location ) ){
$data['location'] = array_shift($parts);
}else{
$data['location'] = NULL;
};

if( in_array( end( $parts), $options_language ) ){
$data['language'] = array_pop($parts);
}else{
$data['language'] = NULL;
};

if( in_array( end( $parts), $options_color ) ){
$data['colormode'] = array_pop($parts);
}else{
$data['colormode'] = NULL;
};

$data['content'] = implode( ' ', $parts );
print_r( $data );

关于文件名的PHP正则表达式

5 个答案: