Question

好的，我想要发生的是当用户注销时我的脚本应该检查代码2的url并向用户显示他们已经注销。如果1有密码或用户名错误，3不确定他们是如何到达那里的。它拉出正确的数字，但只显示1的消息。我不知道什么是错的：/

<?php
$err = $_GET['err'];
echo $err;//Proof the code is getting number
if ($err = "1") {
echo '<center><span class="error-box">'; echo "Whoops! Wrong Username or Password. Please try again.</span></center>";
} 
elseif ($err = '2') {
echo '<center><span class="info-box">'; echo "You Have Been Succesfully Logged Out.</span></center>";
} 
else {
echo '<center><span class="info-box">'; echo "Whoops! Somthing funny happened and were not quite sure what your trying to do. Please try again.</span></center>";
}
?>

Answer 1

因为比较运算符是==，而不是=。

所以你需要

if ($err == "1") {

其他问题如果声明

1 个答案: