尝试使用实体框架映射以下架构。
这导致VS中的以下映射。
这是DB脚本:
USE [TestDb]
GO
/****** Object: Table [dbo].[Customer] Script Date: 06/20/2009 09:53:52 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE TABLE [dbo].[Customer](
[CustomerId] [uniqueidentifier] NOT NULL,
[FirstName] [nvarchar](50) NOT NULL,
[LastName] [nvarchar](50) NOT NULL,
CONSTRAINT [PK_Customer] PRIMARY KEY CLUSTERED
(
[CustomerId] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
GO
/****** Object: Table [dbo].[Store] Script Date: 06/20/2009 09:53:52 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE TABLE [dbo].[Store](
[StoreId] [uniqueidentifier] NOT NULL,
[StoreName] [nvarchar](50) NOT NULL,
[TopCustomer] [uniqueidentifier] NULL,
CONSTRAINT [PK_Store] PRIMARY KEY CLUSTERED
(
[StoreId] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
GO
/****** Object: Table [dbo].[CustomerStore] Script Date: 06/20/2009 09:53:52 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE TABLE [dbo].[CustomerStore](
[CustomerId] [uniqueidentifier] NOT NULL,
[StoreId] [uniqueidentifier] NOT NULL,
CONSTRAINT [PK_CustomerStore] PRIMARY KEY CLUSTERED
(
[CustomerId] ASC,
[StoreId] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
GO
/****** Object: ForeignKey [FK_CustomerStore_Customer] Script Date: 06/20/2009 09:53:52 ******/
ALTER TABLE [dbo].[CustomerStore] WITH CHECK ADD CONSTRAINT [FK_CustomerStore_Customer] FOREIGN KEY([CustomerId])
REFERENCES [dbo].[Customer] ([CustomerId])
ON UPDATE CASCADE
ON DELETE CASCADE
GO
ALTER TABLE [dbo].[CustomerStore] CHECK CONSTRAINT [FK_CustomerStore_Customer]
GO
/****** Object: ForeignKey [FK_CustomerStore_Store] Script Date: 06/20/2009 09:53:52 ******/
ALTER TABLE [dbo].[CustomerStore] WITH CHECK ADD CONSTRAINT [FK_CustomerStore_Store] FOREIGN KEY([StoreId])
REFERENCES [dbo].[Store] ([StoreId])
ON UPDATE CASCADE
ON DELETE CASCADE
GO
ALTER TABLE [dbo].[CustomerStore] CHECK CONSTRAINT [FK_CustomerStore_Store]
GO
/****** Object: ForeignKey [FK_Store_TopCustomer] Script Date: 06/20/2009 09:53:52 ******/
ALTER TABLE [dbo].[Store] WITH CHECK ADD CONSTRAINT [FK_Store_TopCustomer] FOREIGN KEY([TopCustomer])
REFERENCES [dbo].[Customer] ([CustomerId])
GO
ALTER TABLE [dbo].[Store] CHECK CONSTRAINT [FK_Store_TopCustomer]
GO
问题:
如何在不在Customer类上创建额外导航属性的情况下将TopCustomer关联映射到Customer的单个实例?
答案 0 :(得分:4)
听起来你已经有模型工作和映射了吗?
但你只需要删除额外的导航属性吗?
如果你想删除导航属性,它很简单(尽管你不能做标准的EF设计师)。
您只需在XML编辑器中打开EDMX文件(在VS中很容易)并从客户实体中删除不需要的<NavigationProperty .../>
。
这种关系在模型中仍然存在,但在课堂上你只能来自 Store.TopCustomer
你不能走另一条路。
希望这有帮助
亚历
Microsoft的项目经理实体框架团队。