Question

我有以下实体

@Entity
public class Conversation implements Serializable {

    @Id
    private int Id;

    @Column
    private Alias AliasA;

    // SNIP
}

和

@Entity
public class Alias implements Serializable {

    @Id
    private String alias;

    @Column
    private String personalName;

    @OneToMany(mappedBy = "alias", cascade = CascadeType.ALL)
    @MapKeyColumn(name="address")
    private Map<String, Recipient> recipients = new HashMap<String, Recipient>();
}

和

@Entity
public class Recipient implements Serializable {

    @Id
    @GeneratedValue
    private long id;

    @Column
    private String address;

    @Column
    private RecipientStatus status;

    @ManyToOne
    private Alias alias;
}

我想制作类似下面的JPQL查询

SELECT conversation FROM Conversation conversation WHERE :sender MEMBER OF conversation.aliasA.recipients AND conversation.adId=:adID

:sender位于我的地图键中。但是，MEMBER OF关键字似乎只适用于集合，而不适用于地图。我相信JPA 2.0应该提供KEY关键字，但这似乎还没有在OpenJPA中实现。有替代方案吗？

更新：添加信息以澄清我的问题。

Answer 1

有一个VALUE关键字可以允许您这样的内容：

SELECT c FROM Conversation c JOIN c.aliasA a JOIN a.recepients r 
WHERE VALUE(r) = :sender AND conversation.adId=:adID

Answer 2

虽然axtavt的答案给了我所需的提示，但答案实际上是，在这种情况下，IntelliJ 10.5.4中的错误检查不值得信任。

KEY关键字确实有效，正确的查询是

SELECT conversation FROM Conversation conversation JOIN conversation.aliasA.recipients recipients WHERE KEY(recipients) = :senderAddress AND conversation.adId=:adID

在OpenJPA中使用地图查询实体

2 个答案: