我跟着official documentation使用symfony 2标准发行版提供的安全性来验证我的用户,通过Doctrine2将它们保存在数据库中,看起来配置的一切都还可以,但我总是得到同样的错误:Bad Credentials
。
我使用DoctrineFixturesBundle加载一些用户和角色,似乎完成加载确定。所以,我认为这个问题在认证过程中的某个地方,对我来说是透明的...我不知道如何调试这个并且会感谢任何帮助......
谢谢!如果您需要任何其他代码段,请告诉我,我将编辑问题。我没有在这里粘贴代码,以使问题更具可读性......
编辑2 :正如@Dieter所建议的那样,我检查了日志,似乎没有数据传递给查询,这非常奇怪,因为我遵循他们提到的每个约定在the cookbook ...这里也是我的登录表单的定义。抱歉,这个问题很长!任何帮助将不胜感激!
LoginType.php的片段:
public function buildForm(FormBuilder $builder, array $options) {
$builder->add('_username', 'text', array(
'label' => 'Email ',
'required' => true,
));
$builder->add('_password', 'password', array(
'label' => 'Password ',
'required' => true,
));
$builder->add('_remember_me', 'checkbox', array(
'label' => 'Remember me ',
'required' => false,
));
}
app / logs / dev.log输出:
[2012-04-17 03:43:01] event.DEBUG: Notified event "kernel.request" to listener
"Symfony\Component\Security\Http\Firewall::onKernelRequest".
[] []
[2012-04-17 03:43:01] doctrine.DEBUG: SET NAMES UTF8 ([]) [] []
[2012-04-17 03:43:01] doctrine.DEBUG: SELECT t0.id AS id1, t0.username AS
username2, t0.salt AS salt3, t0.password AS password4,
t0.is_active AS is_active5, t0.mailer_id AS mailer_id6
FROM SfUser t0 WHERE t0.username = ? (["NONE_PROVIDED"])
[] []
[2012-04-17 03:43:01] security.INFO: Authentication request failed: Bad
credentials [] []
[2012-04-17 03:43:01] security.DEBUG: Redirecting to / [] []
修改: 由于我的pastebin链接已过期,并且正如Peter Porfey所建议的那样,这是代码:
这是我的security.yml
security:
encoders:
ElCuadre\AccountBundle\Entity\User: sha512
role_hierarchy:
ROLE_ADMIN: [ROLE_USER, ROLE_PROVIDER]
ROLE_SUPER_ADMIN: [ROLE_USER, ROLE_PROVIDER, ROLE_ADMIN, ROLE_ALLOWED_TO_SWITCH]
providers:
user_db:
entity: { class: ElCuadre\AccountBundle\Entity\User, property: username}
firewalls:
dev:
pattern: ^/(_(profiler|wdt)|css|images|js)/
security: false
secured_area:
pattern: ^/
anonymous: ~
form_login:
login_path: /
check_path: /login_check
logout:
path: /logout
target: /
remember_me:
key: %secret%
lifetime: 3600
path: /
domain: ~ # Defaults to the current domain from $_SERVER
access_control:
- { path: ^/$, roles: IS_AUTHENTICATED_ANONYMOUSLY }
和我的控制员:
public function loginAction() {
$request = $this->getRequest();
$session = $request->getSession();
// get the login error if there is one
if ($request->attributes->has(SecurityContext::AUTHENTICATION_ERROR)) {
$error = $request->attributes->get(SecurityContext::AUTHENTICATION_ERROR);
} else {
$error = $session->get(SecurityContext::AUTHENTICATION_ERROR);
$session->remove(SecurityContext::AUTHENTICATION_ERROR);
}
$form = $this->createForm(new LoginType());
return $this->render(
'ElCuadreAccountBundle:Auth:login.html.twig',
array(
'form' => $form->createView(),
'last_username' => $session->get(
SecurityContext::LAST_USERNAME),
'error' => $error,
)
);
}
以下是灯具文件的代码:
<?php
namespace ElCuadre\AccountBundle\DataFixtures\ORM;
use Doctrine\Common\Persistence\ObjectManager;
use Doctrine\Common\DataFixtures\FixtureInterface;
use Doctrine\Common\DataFixtures\AbstractFixture;
use ElCuadre\AccountBundle\Entity\User;
use ElCuadre\AccountBundle\Entity\Role;
use Symfony\Component\DependencyInjection\ContainerAwareInterface;
use Symfony\Component\DependencyInjection\ContainerInterface;
class LoadAccountData extends AbstractFixture implements FixtureInterface, ContainerAwareInterface {
private $container;
public function setContainer(ContainerInterface $container = null) {
$this->container = $container;
}
private function loadRole($manager, $name, $roleName) {
$role = new Role();
$role->setName($name);
$role->setRole($roleName);
$manager->persist($role);
$manager->flush();
return $role;
}
private function loadUser($manager, $username, $password, $roles) {
$user = new User();
$user->setUsername($username);
$encoder = $this->container->get('security.encoder_factory')->getEncoder($user);
$user->setPassword($encoder->encodePassword($password, $user->getSalt()));
foreach ($roles as $role) {
$user->addRole($role);
}
$manager->persist($user);
$manager->flush();
}
public function load(ObjectManager $manager) {
// Roles:
$roleUser = $this->loadRole($manager, 'user', 'ROLE_USER');
$roleProvider = $this->loadRole($manager, 'provider', 'ROLE_PROVIDER');
$roleAdmin = $this->loadRole($manager, 'admin', 'ROLE_ADMIN');
$roleSuperAdmin = $this->loadRole($manager, 'superadmin', 'ROLE_SUPER_ADMIN');
// Users:
$this->loadUser($manager, 'user@elcuadre.com', 'userpass', $roleUser);
$this->loadUser($manager, 'provider@elcuadre.com', 'providerpass', $roleProvider);
$this->loadUser($manager, 'admin@elcuadre.com', 'adminpass', $roleAdmin);
$this->loadUser($manager, 'superadmin@elcuadre.com', 'superadminpass', $roleSuperAdmin);
}
}
答案 0 :(得分:9)
如果我发生类似的错误,app / logs / dev.log或系统日志中会显示某种问题,例如/var/log/apache2/error.log。
你看到有什么东西突然冒出来了吗?
编辑:作为对您新信息的反应
您自己构建该表单是否有原因?如您引用的文档中所述,您可以只创建树枝模板并为字段指定名称“_username”和“_password”。那么魔法应该为你完成。