Question

我在我的数据库中使用以下查询

SELECT b.sales_id,b.category_id,b.sale_starts,b.sale_ends 
FROM tbl_sales b WHERE b.active=1 
UNION
SELECT b.sales_id,b.category_id,b.sale_starts,b.sale_ends 
FROM tbl_sales b INNER JOIN tb_category c ON  b.category_id=c.cat_id 
WHERE c.cat_keyword LIKE 'a' ORDER BY sale_ends  DESC

并获得如下结果，

sales_id  | category_id         |sale_starts | sale_ends 
----------|---------------------|------------|--------------
 1        |   10                | 2012-03-31 | 2012-04-30     
 2        |   11                | 2012-03-22 | 2012-04-27
 3        |   25                | 2012-03-31 | 2012-04-25
 4        |   12                | 2012-04-05 | 2012-04-11

现在我需要获得如下结果，即必须在订单顶部显示具有today's date/current date as sale_ends的行（假设今天的日期/当前日期为2012-04-11），如图所示下面 -

sales_id      | category_id         |sale_starts | sale_ends 
    ----------|---------------------|------------|--------------
     4        |   12                | 2012-04-05 | 2012-04-11 (today's date)
     1        |   10                | 2012-03-31 | 2012-04-30     
     2        |   11                | 2012-03-22 | 2012-04-27
     3        |   25                | 2012-03-31 | 2012-04-25

需要帮助，谢谢。

Answer 1

尝试使用条件 -

的ORDER BY子句

ORDER BY IF(sale_ends = DATE(NOW()), 0, 1), sale_ends DESC

Answer 2

您可以将整个事物包装在另一个SELECT中并使用ORDER BY

SELECT * FROM (     
     SELECT b.sales_id,b.category_id,b.sale_starts,b.sale_ends 
     FROM tbl_sales b WHERE b.active=1 
     UNION
     SELECT b.sales_id,b.category_id,b.sale_starts,b.sale_ends 
     FROM tbl_sales b INNER JOIN tb_category c ON  b.category_id=c.cat_id 
     WHERE c.cat_keyword LIKE 'a' ORDER BY sale_ends  DESC
) AS all_sales
ORDER BY (sale_ends=CURDATE()) DESC, sale_ends DESC

MySQL查询以按降序显示当前日期和其他日期的记录

2 个答案: