Question

我正在尝试在代码中实现计时器，我发现的所有示例都使用while(1)或for(;;)，但当我尝试使用scanf时，我的程序终止。它是否在stdin上获得任何值，因为如果我使用scanf两次，则在退出程序之前调用timer两次。这是我的示例代码：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#include <signal.h>
#include <netinet/in.h>
#include <signal.h>
#include <time.h>

#include <linux/socket.h>
#include <time.h>


#define SIGTIMER (SIGRTMAX)
#define SIG SIGUSR1
static timer_t     tid;
static timer_t     tid2;

void SignalHandler(int, siginfo_t*, void* );
timer_t SetTimer(int, int);

int main(int argc, char *argv[]) {

    int t;

    printf("SIGRTMAX %d\n", SIGRTMAX);
        printf("SIGRTMIN %d\n", SIGRTMIN);

    struct sigaction sigact;
    sigemptyset(&sigact.sa_mask);
    sigact.sa_flags = SA_SIGINFO;
    sigact.sa_sigaction = SignalHandler;
    // set up sigaction to catch signal
    if (sigaction(SIGTIMER, &sigact, NULL) == -1) {
        perror("sigaction failed");
        exit( EXIT_FAILURE );
    }

    // Establish a handler to catch CTRL+c and use it for exiting.
    sigaction(SIGINT, &sigact, NULL);
    tid=SetTimer(SIGTIMER, 1000);

    struct sigaction sa;
    sigemptyset(&sa.sa_mask);
    sa.sa_flags = SA_SIGINFO;
    sa.sa_sigaction = SignalHandler;
    // set up sigaction to catch signal
    if (sigaction(SIG, &sa, NULL) == -1) {
        perror("sa failed");
        exit( EXIT_FAILURE );
    }

    // Establish a handler to catch CTRL+c and use it for exiting.
    sigaction(SIGINT, &sa, NULL);
    tid2=SetTimer(SIG, 1000);

   // for(;;);  or while(1) Working properly

    scanf("%d", &t); /// Program terminates
    return 0;
}

void SignalHandler(int signo, siginfo_t* info, void* context)
{


    if (signo == SIGTIMER) {
        printf("Command Caller has ticked\n");

    }else if (signo == SIG) {
        printf("Data Caller has ticked\n");

    } else if (signo == SIGINT) {
        timer_delete(tid);
        perror("Crtl+c cached!");
        exit(1);  // exit if CRTL/C is issued
    }
}
timer_t SetTimer(int signo, int sec)
{
    static struct sigevent sigev;
    static timer_t tid;
    static struct itimerspec itval;
    static struct itimerspec oitval;

    // Create the POSIX timer to generate signo
    sigev.sigev_notify = SIGEV_SIGNAL;
    sigev.sigev_signo = signo;
    sigev.sigev_value.sival_ptr = &tid;

    if (timer_create(CLOCK_REALTIME, &sigev, &tid) == 0)
    {

        itval.it_value.tv_sec = sec / 1000;
        itval.it_value.tv_nsec = (long)(sec % 1000) * (1000000L);
        itval.it_interval.tv_sec = itval.it_value.tv_sec;
        itval.it_interval.tv_nsec = itval.it_value.tv_nsec;



        if (timer_settime(tid, 0, &itval, &oitval) != 0)
        {
            perror("time_settime error!");
        }
    }
    else
    {
        perror("timer_create error!");
        return NULL;
    }
    return tid;
}

那么，我该如何解决这个问题呢？任何帮助，将不胜感激。谢谢，Yuvi

Answer 1

信号中断scanf。如果在scanf输出后添加perror('scanf')将是：

SIGRTMAX 64
SIGRTMIN 34
Command Caller has ticked
Data Caller has ticked
scanf: Interrupted system call

如果您将scanf替换为：

do {
    errno = 0;
    scanf("%d", &t);
} while(errno == EINTR);

scanf将在Interrupted system call失败时重试。

Answer 2

您绝对不能在信号处理程序中使用printf和perror。它们不是可重入的。

此外，如果您的程序在其中收到信号，scanf可能会返回错误。如果scanf返回EOF，请检查errno，它可能是EINTR。

如果我使用scanf，程序将终止

2 个答案: