LuaInterface:访问对象属性

时间:2012-04-08 13:31:44

标签: c# lua luainterface

我正在使用LuaInterface为我希望在Lua中提供的某些对象注册一个getter。 E.G:

    public MyObject getObjAt(int index)
    {
        return _myObjects[index];
    }

我的Lua文件:

obj = getObjAt(3) 
print(obj.someProperty)    // Prints "someProperty"
print(obj.moooo)           // Prints "moooo"
print(obj:someMethod())    // Works fine, method is being executed

在Lua中返回后,我如何才能访问公共对象属性?这是可能的,还是我必须为每个对象属性编写getter?

1 个答案:

答案 0 :(得分:0)

您可能会发现此代码对于了解如何访问属性非常有用:

class Lister
{
    public string ListObjectMembers(Object o)
    {
        var result = new StringBuilder();
        ProxyType proxy = o as ProxyType;

        Type type = proxy != null ? proxy.UnderlyingSystemType : o.GetType();

        result.AppendLine("Type: " + type);

        result.AppendLine("Properties:");
        foreach (PropertyInfo propertyInfo in type.GetProperties())
            result.AppendLine("   " + propertyInfo.Name);

        result.AppendLine("Methods:");
        foreach (MethodInfo methodInfo in type.GetMethods())
            result.AppendLine("   " + methodInfo.Name);


        return result.ToString();
    }
}

并注册函数:

static Lister _lister = new Lister();
private static void Main() {
    Interpreter = new Lua();

    Interpreter.RegisterFunction("dump", _lister,
    _lister.GetType().GetMethod("ListObjectMembers"));
}

然后在Lua:

print(dump(getObjAt(3)))