Question

我有一个定义常量变量的文件，如下所示：

define_vars.php

<?

define("something","value");
define("something1","value");
define("something2","value");
define("something3","value");

我有一个函数解析$var作为常量变量名，如下所示：

function something($var=''){

include('define_vars.php');

// $var is the name of one of the variables I am defining in the other file (define_vars.php)
// So $var may have a value of "something3", which is the name of one of the constants defined in the other file...

}

我需要以某种方式获取常量的值，当$ var保存常量的名称时我希望得到的值....有意义吗？：S

任何想法？

Answer 1

http://php.net/constant

function something($var) {
    if (defined($var)) {
        $value = constant($var);
    }
}

此外，您应确保包含定义的文件仅包含一次，因此请改用require_once('define_vars.php');。

Answer 2

您想要constant()

constant($var); // value

Answer 3

使用constant()获取值。你可以做这样的事情

function something($var = '') {
    include_once('define_vars.php'); //you don't want to include the file more than once or it will cause a fatal error when trying to redefine your constants
    return (defined($var) ? constant($var) : null);
}

如何在函数中动态访问常量变量（在另一个文件中定义）？

3 个答案: