我有两个表的mysql数据库。
第一(资料)
+---------+------+----------+
| species | sex | user |
+---------+------+----------+
| bird | NULL | 1 |
| bird | f | 1 |
| cat | f | 1 |
| cat | m | 1 |
| dog | f | 1 |
| dog | m | 2 |
| hamster | f | 2 |
| snake | m | 1 |
+---------+------+----------+
第二(用户)
+--------+-----+
| user | id |
+--------+-----+
| amy | 1 |
| dav | 2 |
| mot | 3 |
| mmm | 4 |
| aaw | 5 |
| dsa | 6 |
+--------+-----+
我想计算并显示表“users”中每个用户行的表“information”的值 喜欢这个
+---------+------+----------+
| user | id | count |
+---------+------+----------+
| amy | 1 | 6 |
| dav | 2 | 2 |
| mot | 3 | 0 |
| mmm | 4 | 0 |
| aaw | 5 | 0 |
| dsa | 6 | 0 |
+---------+------+----------+
我该如何进行此查询?
答案 0 :(得分:1)
select users.user, users.id, count (species.name)
from users left join species
on users.id = species.user
group by users.user, users.id
order by count (species.name) desc
答案 1 :(得分:0)
不是这样的:
select u.user, u.id, count(i.user)
from user u
inner join information i on i.user = u.id
group by u.user, u.id