Question

我正在尝试编辑文本文件中的一行，但在编辑文件时我有一个意外的行为。我想要做的是调整看起来像的文本的特定行（点数：100）。在函数中，我通过值传递参数，要调整的新硬币和文件与ftell-> user_point的偏移量。我得到的输出结果很奇怪。我尝试使用已编辑的行将文件的其余部分复制到temp，然后将其从我复制到temp的点复制回原始文件（这就是带有ftell的user_point偏移量）。这是原始的fie，有这样的条目：

...    
_______________________________________
    nickname     : geo
    password     : cuvctq
    Name         : george
    Surname      : papas
    points       : 100
    participated : 
    past draws   : 0
    Chosen No.   : 
    future draws : 0
    Registered   : Sun Feb 05 19:23:50 2012
...

第二次编辑后我得到的是：

...
    _______________________________________
    nickname     : geo
    password     : cuvctq
    Name         : george
    Surname      : papaspoints       : 98
    participated : 
    past draws   : 0
    Chosen No.   : 
    future draws : 0
    Registered   : Sun Feb 05 19:23:50 2012
...
At the end of the text i get one extra \n after i edit the 
file whch is something i dont want :/

因此进一步编辑将破坏文本... 我还得到一个额外的EXTRA \ n，至少我认为是这样，是"r+"模式，这也是我不想要的......

void coins_adjust(int coins_new,int user_point)
{
    int lines,i,ln_point_copy;
    char buffer[50],buff_copied[50];
    FILE *lottary,*temp;

    memset(buff_copied,'\0',sizeof(char)*50);
    lottary=fopen("customers.txt","r");
    temp=fopen("temp.txt","w");
    fseek(lottary,user_point,SEEK_SET);
    for (lines=0;lines<5;lines++)
    {
        memset(buffer,'\0',sizeof(char)*50);
        if (lines==5)
            ln_point_copy=ftell(lottary);       //from TEMP to CUSTOMERS
        fgets (buffer ,50 , lottary);
    }
    coins_new+=atoi(buffer+15);

    strncpy(buff_copied,buffer,15);     //copy 15 chars and fill with null
    memset(buffer,'\0',sizeof(char)*50);
    itoa (coins_new,buffer,10);          //fix the new line to be entered
    strcat(buff_copied,buffer);          //the edited line is as it is supposed
    strcat(buff_copied,"\n");            //to be with \n at the end.
    puts(buff_copied);

    printf("%s",buff_copied);fflush(stdout);
    fprintf(temp,"%s",buff_copied);
    for(i=getc(lottary); i!=EOF; i=getc(lottary))  //copy to temp
    {
        putc(i, temp);
    }
    fclose(lottary);
    fclose(temp);

    temp=fopen("temp.txt","r");
    lottary=fopen("customers.txt","r+");
    fseek(lottary,ln_point_copy,SEEK_SET);
    for(i=getc(temp); i!=EOF; i=getc(temp))     //copy until eof
    {
        putc(i, lottary);
    }
    fclose(lottary);fclose(temp);

}

我已经调试了程序，一切似乎至少在传递给我存储行字符的数组的值，但我不知道为什么它在我尝试时忽略前一行的\n把它复制回原来......似乎有一个\r字符，当我复制回原版时，我无法摆脱它... 提前谢谢。

Answer 1

我更想到这样的事情：

void change_points(int new_points)
{
    FILE *input  = fopen("customers.txt", "r");
    FILE *output = fopen("temp.txt", "w");

    char buffer[256];

    while (fgets(buffer, sizeof(buffer), input))
    {
        /* Look for the correct line */
        /* Can also use e.g. "if (strncmp(buffer, "points", 6) == 0)"
         * if it's at the start of the line
         */
        if (strstr(buffer, "points") != NULL)
        {
            int old_points;

            sscanf(buffer, "%*s : %d ", &old_points);

            /* Format how you like it */
            fprintf(output, "%-13s: %d\n", "points", new_points + old_points);
        }
        else
            fputs(buffer, output);
    }

    fclose(output);
    fclose(input);

    /* The file "temp.txt" now contains the modifeed text */
    /* Copy either using "fgets"/"fputs", or using "fread"/"fwrite" */

    input  = fopen("temp.txt", "r");
    output = fopen("customers.txt", "w");

    while (fgets(buffer, sizeof(buffer), input))
        fputs(buffer, output);

    fclose(output);
    fclose(input);
}

它更短，更简单，可能更有效（逐行循环而不是char-by-char），并且您要查找的行可以在文件中的任何位置，而无需您知道其确切位置。

使用临时文件C在文本文件中编辑一行

1 个答案: