Question

我有一个表（Inventory_Line），其中LID是自动递增的，IID是指代库存日期的单个数字，PID是数字部分＃。我们将此表用于库存。

LID  IID  NAME    PID  QTY
---  ---  ------  ---  ---
1    1    Part A  213  12
2    1    Part B  200  15
3    2    Part A  213  9
4    2    Part B  200  7

我们还有一个表Order_Line

OLID  OID  NAME    PID  QTY
----  ---  ------  ---  ---
1     217  Part A  213  12
2     217  Part B  200  15
3     218  Part A  213  9
4     218  Part B  200  7

我的目标是展示

((Previous Inventory Qty (Inventory_Line.IID=1)) AS PREV_INV + 
(ORDERED Qty (Order_Line.OID = 217 AND 218)) AS ORDERED - 
(Current Inventory Qty Inventory_Line.IID=2) AS CURRENT_INV) AS SOLD 
WHERE PID = X

输出如下：

PID  NAME    PREV_INV  ORDERED  CURRENT_INV  SOLD
---  ------  --------  -------  -----------  ----
213  Part A  12        21       9            24

我们正在使用MS Access，而且我对联接有一些经验，但我有点不知道如何解决这个问题。任何帮助将不胜感激。

Answer 1

你是否正在考虑这些问题？

SELECT t.pid,
       Nz([pi].[qty], 0) + Nz([o].[qty], 0) - Nz([s].[qty], 0) AS dat
FROM   (((SELECT DISTINCT pid
         FROM   inventory_line) AS t
         LEFT JOIN (SELECT *
                    FROM   inventory_line
                    WHERE  iid = 2) AS pi
           ON t.pid = pi.pid)
        LEFT JOIN (SELECT *
                   FROM   inventory_line
                   WHERE  iid = 3) AS s
          ON t.pid = s.pid)
       LEFT JOIN (SELECT *
                  FROM   order_line
                  WHERE  oid = 217
                          OR oid = 218) AS o
         ON t.pid = o.pid
WHERE  (( ( t.pid ) = [Enter:] ))

上面需要做一些工作，但是如果想要输出更多的输入，应该做些什么会更清楚。

重新评论

SELECT t.pid,
       t.name,
       pi.qty,
       o.q,
       s.qty,
       Nz([pi].[qty]) + Nz([o].[q]) - Nz([s].[Qty]) AS sold
FROM   (((SELECT DISTINCT pid,
                         [Name]
         FROM   inventory_line) AS t
         LEFT JOIN (SELECT pid,
                           qty
                    FROM   inventory_line
                    WHERE  iid = 1) AS pi
           ON t.pid = pi.pid)
        LEFT JOIN (SELECT pid,
                          qty
                   FROM   inventory_line
                   WHERE  iid = 2) AS s
          ON t.pid = s.pid)
       LEFT JOIN (SELECT pid,
                         SUM(qty) AS q
                  FROM   order_line
                  WHERE  oid = 217
                          OR oid = 218
                  GROUP  BY pid) AS o
         ON t.pid = o.pid
WHERE  (( ( t.pid ) = [Enter:] ))

Answer 2

我无法确定SOLD列中的24来自哪里，但这是另一种解决方案

SELECT Order_Line.PID, Order_Line.NAME, DLookUp("[QTY]","[Order_Line]","[OID]=" & [OID]-1 & " AND PID=" & [PID]) AS PREV_INV, DSum("[QTY]","[Order_Line]","[PID]=" & [PID]) AS ORDERED, Order_Line.QTY AS CURRENT_INV FROM Order_Line;

多个Sql查询相同的字段

2 个答案: