Question

我使用的完整代码：

 $query18 = 'SELECT group_concat(id) as qc10 FROM tblorders WHERE date LIKE \'' . date ('Y-m-') . '%\'';
    $result18 = mysql_query($query18);
    $data18 = mysql_fetch_array($result18);
    $qc10 = $data18['qc10'];
  $query19 = "SELECT count(id) as qc11 FROM bl_orderitems WHERE orderid=$qc10";
    $result19 = mysql_query($query19);
    $data19 = mysql_fetch_array($result19);

$ query19如下所示：

'SELECT count(id) FROM bl_orderitems WHERE orderid=7,6,8,9,10,11,12,13,14';

但它不起作用。如何列出这些ID，以便实际工作？

谢谢！

Answer 1

使用WHERE orderid IN(7,6,8,9,10,11,12,13,14)

所以查询将是：

'SELECT count(id) FROM bl_orderitems WHERE orderid IN(7,6,8,9,10,11,12,13,14)';

Answer 2

尝试使用IN

SELECT count（id）FROM bl_orderitems WHERE orderid IN（7,6,8,9,10,11,12,13,14）

Answer 3

如果您希望匹配orderid的值，这是您列出的选项之一，则应该有效：

SELECT count(orderid) FROM bl_orderitems WHERE orderid IN (7,6,8,9,10,11,12,13,14);

有问题的mysql查询如何按多个ID过滤

3 个答案: