Question

我在NSString中有一个带有http：//的文本。我想从NSString获取该http链接。如何从字符串中获取link / url？例如：'Stack over flow是初学者https://stackoverflow.com/'非常有用的链接。我想从文本中获取“https://stackoverflow.com/”。我怎样才能做到这一点？提前谢谢。

Answer 1

我不确定您的链接是什么意思，但如果您想将NSString转换为NSURL，则可以执行以下操作：

NSString *urlString = @"http://somepage.com";
NSURL *url = [NSURL URLWithString:urlString];

修改

这是如何获取给定NSString中的所有URL：

NSString *str = @"This is a grate website http://xxx.xxx/xxx you must check it out"; NSArray *arrString = [str componentsSeparatedByString:@" "]; for(int i=0; i<arrString.count;i++){ if([[arrString objectAtIndex:i] rangeOfString:@"http://"].location != NSNotFound) NSLog(@"%@", [arrString objectAtIndex:i]); }

Answer 2

您可以直接搜索以@“http：//”开头的子字符串，而不是将字符串拆分成数组并弄乱这种方式：

NSString *str = @"Stack over flow is very useful link for the beginners http://stackoverflow.com/";
// get the range of the substring starting with @"http://"
NSRange rng = [str rangeOfString:@"http://" options:NSCaseInsensitiveSearch];

// Set up the NSURL variable to hold the created URL
NSURL *newURL = nil;

// Make sure that we actually have found the substring
if (rng.location == NSNotFound) {
    NSLog(@"URL not found");
    // newURL is initialised to nil already so nothing more to do.
} else {
    // Get the substring from the start of the found substring to the end.
    NSString *urlString = [str substringFromIndex:rng.location];

    // Turn the string into an URL and put it into the declared variable
    newURL = [NSURL URLWithString:urlString];
}

Answer 3

试试这个：

nsstring *str = @"Stack over flow is very useful link for the beginners http://stackoverflow.com/";

nsstring *http = @"http";
nsarray *arrURL = [str componentsSeparatedByString:@"http"];

这将在nsarray中提供两个对象。第一个对象将具有：Stack over flow is very useful link for the beginners，第二个将是：://stackoverflow.com/（我猜）

那么你可以这样做：

  NSString *u = [arrURL lastObject];

然后做：

nsstring *http = [http stringByAppendingFormat:@"%@",u];

相当冗长，但我认为这对你有用。希望对你有帮助。

如何在iPhone中的NSString中查找并获取URL？

3 个答案: