Question

这是从先前通过stackoverflow（Returning nearest date to date in a different table）解决的查询继续进行的，但是，我现在希望进一步开发它。

我的SQL是：

SELECT *
FROM (SELECT O_ASSESSMENTS.ASM_SUBJECT_ID as "P Number", 
             O_ASSESSMENTS.ASM_ID as "Assessment ID", 
             O_ASSESSMENTS.ASM_START_DATE as "Assessment Start",  
             O_ASSESSMENTS.ASM_END_DATE as "Assessment End", 
             O_SERVICE_EVENTS.SEV_ID as "Event ID", 
             O_SERVICE_EVENTS.SEV_ACTUAL_DATE as "Event Start", 
             O_SERVICE_EVENTS.SEV_OUTCOME_DATE as "Event End",
             ROUND(O_ASSESSMENTS.ASM_START_DATE -O_SERVICE_EVENTS.SEV_ACTUAL_DATE,0) as "Likely",
             row_number() over(PARTITION BY  O_ASSESSMENTS.ASM_ID                                    
                               ORDER BY abs(O_ASSESSMENTS.ASM_START_DATE -  O_SERVICE_EVENTS.SEV_ACTUAL_DATE))as "Row Number"            
      FROM O_ASSESSMENTS 
      JOIN O_SERVICE_EVENTS
        ON O_ASSESSMENTS.ASM_SUBJECT_ID = O_SERVICE_EVENTS.SEV_SUBJECT_ID
      Where O_SERVICE_EVENTS.SEV_CODE IN ('ICS_E3','CPINVEST') AND 
            O_ASSESSMENTS.ASM_QSA_ID  IN ('AA1329','AA521') )
WHERE "Row Number" = 1

基本上，我们有两个表--o_assessments和o_service_events，这个SQL将最近的服务事件返回给评估。现在我想在查询中包含一些更多的上下文信息，以使其对最终用户更有帮助 - 即团队名称和工作者名称。

不幸的是，团队和工作人员再次在不同的表中（o_responsibilities），并通过asm_id链接到o_assessments到res_rec_id。

问题是，我真的不确定如何将这个表调用到上面的sql中 - 所以任何建议都会非常感激！

我还想知道是否有可能调整现有查询以仅在“可能”字段具有0的差异时返回相应的事件（因为任何更大的可能与该特定评估无关）。我知道我可以将它添加到where，但如果我添加行

and "Likely" = 0

它只返回一个事件的评估，这不会突出显示任何问题（即没有相应事件的评估）。

我一直在学习SQL，但目前看来我手头上还有很多东西，所以任何建议都非常感谢！我不确定是要修改原始查询还是开始新查询，所以我希望我不会无意中侵犯任何规则。

编辑：

好的，按照Mark的解决方案，这就是我的工作。

SELECT 
* 
FROM 
(SELECT 
OAS.ASM_SUBJECT_ID as "P Number",
OAS.ASM_ID as "Assessment ID",
OAS.ASM_START_DATE as "Assessment Start", 
OAS.ASM_END_DATE as "Assessment End",
OAS.ASM_AUTH_DATETIME as "Authorisation Date",
nvl(olm_bo.get_ref_desc(OAS.ASM_OUTCOME,'ASM_OUTCOME'),'') as "Outcome",
nvl(olm_bo.get_org_name(ORE.RES_PARTY_OUN_ID),'') as "Team",
nvl(olm_bo.get_per_name(ORE.RES_PARTY_ID),'') as "Worker",
OSE.SEV_ID as "Event ID",
OSE.SEV_ACTUAL_DATE as "Event Start",
OSE.SEV_OUTCOME_DATE as "Event End",
ROUND(OAS.ASM_START_DATE -OSE.SEV_ACTUAL_DATE,0) as "Likely",
row_number() over(PARTITION BY  OAS.ASM_ID                   
ORDER BY 
abs(OAS.ASM_START_DATE -  OSE.SEV_ACTUAL_DATE))as "Row Number"
FROM O_ASSESSMENTS OAS      
INNER JOIN O_RESPONSIBILITIES ORE ON OAS.ASM_ID = ORE.RES_REC_ID
AND ORE.RES_PARTY_OUN_ID = 'TEAM'
LEFT JOIN O_SERVICE_EVENTS OSE ON OAS.ASM_SUBJECT_ID = OSE.SEV_SUBJECT_ID 
AND            
OSE.SEV_CODE IN ('EVENT') 
AND             
ROUND(OAS.ASM_START_DATE - OSE.SEV_ACTUAL_DATE,0) >= -7
AND
ROUND(OAS.ASM_START_DATE - OSE.SEV_ACTUAL_DATE,0) <= 7
Where OAS.ASM_QSA_ID  IN ('ACODE')
AND
nvl(olm_bo.get_ref_desc(OAS.ASM_OUTCOME,'ASM_OUTCOME'),'') <> 'Abandon' ) WHERE "Row Number" = 1

Answer 1

开始一个新的是正确的行动方针;编辑问题以“添加范围”不是一个好习惯。这属于“添加范围”，因此一个新问题是正确的方法。

SELECT
ID, "Assessment ID", 
"Assessment Start", "Assessment End", "Event ID", 
"Event Start", "Event End", Likely, Team_name, Worker_name
FROM
  (SELECT 
  O_ASSESSMENTS.ASM_SUBJECT_ID as "ID", 
  O_ASSESSMENTS.ASM_ID as "Assessment ID", 
  O_ASSESSMENTS.ASM_START_DATE as "Assessment Start",  
  O_ASSESSMENTS.ASM_END_DATE as "Assessment End", 
  O_SERVICE_EVENTS.SEV_ID as "Event ID", 
  O_SERVICE_EVENTS.SEV_ACTUAL_DATE as "Event Start", 
  O_SERVICE_EVENTS.SEV_OUTCOME_DATE as "Event End",
  ROUND(O_ASSESSMENTS.ASM_START_DATE -O_SERVICE_EVENTS.SEV_ACTUAL_DATE,0) as "Likely",
  row_number() over(PARTITION BY  O_ASSESSMENTS.ASM_ID                                    
    ORDER BY abs(O_ASSESSMENTS.ASM_START_DATE -  
    O_SERVICE_EVENTS.SEV_ACTUAL_DATE))    as "Row    Number",
  RES.TEAM_NAME,
  RES.WORKER_NAME
  FROM O_ASSESSMENTS 
  INNER JOIN  O_SERVICE_EVENTS
    ON O_ASSESSMENTS.ASM_SUBJECT_ID = O_SERVICE_EVENTS.SEV_SUBJECT_ID
  INNER JOIN O_Responsibilities res 
    ON O_Assessments.ASM_ID = res.res_rec_ID
  WHERE O_SERVICE_EVENTS.SEV_CODE IN ('ICS_E3','CPINVEST')
    AND O_ASSESSMENTS.ASM_QSA_ID IN ('AA1329','AA521') )  InnerTable
WHERE "Row Number" = 1 and (Likely = 0 or LIKELY is null)

我在这里所做的只是

在内部选择语句
包含您要求的列，但未提供姓名，因此我在INNER和OUTER选择语句中假设了TEAM_NAME和WORKER_NAME
在对原始帖子的评论之前的联接之前消除了AND
在内部选择中添加了表名的别名，需要加入连接在某些时候到外桌。
将（可能= 0或可能为空）添加到外部where子句
重新格式化SQL以保持可读性。

以上5，可能不太正确，我不完全理解您对没有服务日期的评估的评论。如果是这种情况，如果您想要所有评估和相关服务（如果存在），则评估和服务之间的连接必须是左连接，而不是INNER。目前，您只获得具有相关服务的评估。如果您需要所有评估，可能需要进行其他更改。

因此...

  FROM O_ASSESSMENTS 
  INNER JOIN  O_SERVICE_EVENTS
    ON O_ASSESSMENTS.ASM_SUBJECT_ID = O_SERVICE_EVENTS.SEV_SUBJECT_ID

将成为（仅改为内部左侧）

  FROM O_ASSESSMENTS 
  LEFT JOIN  O_SERVICE_EVENTS
    ON O_ASSESSMENTS.ASM_SUBJECT_ID = O_SERVICE_EVENTS.SEV_SUBJECT_ID

它假设评估总是有责任记录，如果不是那么也需要LEFT加入。

最后，当SEV_Actual_Date为空时，需要考虑当你为LIKELY做什么结果。应该有什么价值？

Answer 2

尝试：

SELECT *
FROM (SELECT OAS.ASM_SUBJECT_ID as "P Number", 
             OAS.ASM_ID as "Assessment ID", 
             OAS.ASM_START_DATE as "Assessment Start",  
             OAS.ASM_END_DATE as "Assessment End", 
             ORE.TEAM,
             ORE.WORKER,
             OSE.SEV_ID as "Event ID", 
             OSE.SEV_ACTUAL_DATE as "Event Start", 
             OSE.SEV_OUTCOME_DATE as "Event End",
             ROUND(OAS.ASM_START_DATE -OSE.SEV_ACTUAL_DATE,0) as "Likely",
             row_number() over(PARTITION BY  OAS.ASM_ID                                    
                               ORDER BY abs(OAS.ASM_START_DATE -  OSE.SEV_ACTUAL_DATE))as "Row Number"            
      FROM O_ASSESSMENTS OAS
      LEFT JOIN O_RESPONSIBILITIES ORE
        ON OAS.ASM_ID = ORE.RES_REC_ID
      LEFT JOIN O_SERVICE_EVENTS OSE
        ON OAS.ASM_SUBJECT_ID = OSE.SEV_SUBJECT_ID AND
           OSE.SEV_CODE IN ('ICS_E3','CPINVEST') AND 
           ROUND(OAS.ASM_START_DATE - OSE.SEV_ACTUAL_DATE,0) = 0
      Where OAS.ASM_QSA_ID  IN ('AA1329','AA521') )
WHERE "Row Number" = 1

请注意，这假设RES_REC_ID是O_RESPONSIBILITIES上的唯一标识符。

Answer 3

您可以将o_responsibilities加入相应ID的内嵌视图，然后在查询中包含其列。

请注意，您需要将where likely = 0位放在外部查询中（使用行号标准），而不是内联视图，因为likely是别名。如果您想要突出显示没有事件的评估，那么您应该执行left join并添加sev_id is null的条件。

这样的事情可以解决问题：

select  *
from   (select    o_assessments.asm_subject_id                      as "P Number", 
                  o_assessments.asm_id                              as "Assessment ID", 
                  o_assessments.asm_start_date                      as "Assessment Start",  
                  o_assessments.asm_end_date                        as "Assessment End", 
                  o_service_events.sev_id                           as "Event Id", 
                  o_service_events.sev_actual_date                  as "Event Start", 
                  o_service_events.sev_outcome_date                 as "Event End",
                  o_responsibilities.[WHATEVER]                     as "Team/Worker Stuff",
                  round(o_assessments.asm_start_date - o_service_events.sev_actual_date,0)
                                                                    as "Likely",
                  row_number() over (partition by o_assessments.asm_id                                    
                                     order by     abs(o_assessments.asm_start_date - o_service_events.sev_actual_date))
                                                                    as rn
        from      o_assessments 
        left join o_service_events
        on        o_service_events.sev_subject_id                    = o_assessments.asm_subject_id
        left join o_responsibilities
        on        o_responsibilities.res_rec_id                      = o_assessments.asm_id
        where     o_service_events.sev_code                         in ('ICS_E3','CPINVEST')
        and       o_assessments.asm_qsa_id                          in ('AA1329','AA521'))
where   rn = 1
and    (likely = 0 or sev_id is null);

从多个表返回相关日期，包括附加表信息

3 个答案: