我有一个等同于此BERT的对象(为易读性而包装):
{"Hello",[{1,"john","john123"},{2,"Michale","michale123"}]}
节点中的:
var S = Bert.bytes_to_string([131,104,2,107,0,5,72,101,108,108,111,108,0,0,0,2,104,3,97,1,107,0,4,106,111,104,110,107,0,7,106,111,104,110,49,50,51,104,3,97,2,107,0,7,77,105,99,104,97,108,101,107,0,10,109,105,99,104,97,108,101,49,50,51,106]);
var Obj = Bert.decode(S);
console.log(obj);
我可以在控制台中看到如下。
{
'0': {
type: 'bytelist',
value: 'Hello',
toString: [ Function ],
repr: [ Function ]
},
'1': [
{
'0': 1,
'1': [ Object ],
'2': [ Object ],
type: 'tuple',
length: 3,
value: [ Object ],
repr: [ Function ],
toString: [ Function ]
},
{
'0': 2,
'1': [ Object ],
'2': [ Object ],
type: 'tuple',
length: 3,
value: [ Object ],
repr: [ Function ],
toString: [ Function ]
}
],
type: 'tuple',
length: 2,
value: [
{
type: 'bytelist',
value: 'Hello',
toString: [ Function ],
repr: [ Function ]
},
[
[ Object ],
[ Object ]
]
],
repr: [ Function ],
toString: [ Function ]
}
如何将输出作为
{"Hello",[{1,"john","john123"},{2,"Michale","michale123"}]}
来自obj?
答案 0 :(得分:3)
使用
Obj['0'].value
获取字符串“hello” 和
Obj['1'].forEach(function(el){
var fst = el['0'] //1,2
var snd = el['1'].value //John,Mihcale
var thd = el['2'].value //john123,michale123
})
您只读“[Object]”,因为console.log不会深入到对象层次结构中,如果您想要显示所有属性,请尝试以下操作:
console.log(require('util').inspect(Obj,false,100))