在PHP中,我可以说
$noun = "bird";
$adjective = "warm;
echo <<<EOT
The $noun is very $adjective
EOT;
并输出
鸟很温暖
有没有办法用函数做到这一点?
function getNoun() { return "bird"; }
function getAdjective() { return "warm"; }
echo <<<EOT
The getNoun() is very getAdjective()
EOT;
和输出
鸟很温暖
答案 0 :(得分:5)
您可以使用variable functions,虽然他们对此感到不满,因为他们与变量变量差别不大......
$a = 'getNoun';
$b = 'getAdjective';
echo <<<EOT
The {$a()} is very {$b()}
EOT;
答案 1 :(得分:2)
您可以在使用之前将其存储在变量中:
$noun = getNoun( );
$adj = getAdjective( );
echo <<<EOT
The {$noun} is very {$adj}
EOT;
答案 2 :(得分:0)
echo "The ";
echo getNoun();
echo " is very ";
echo getVerb();
或者甚至(不是100%肯定):
echo "The " . getNoun() . " is very " . getVerb();
答案 3 :(得分:0)
这是一个使用变量函数的解决方案,尽管不完全是:
$noun=function($type){
return $type;
};
$adjective=function($adj){
return $adj;
};
echo "{$noun("Robin")} was very {$adjective("Warm")}";