我有一个自我参照表,我用kodo jdo 4(从weblogic服务器10.3.4提供)映射。我的代码将通过增强器,但当我尝试使用它时,我得到错误:< / p>
<openjpa-1.1.1-SNAPSHOT-r422266:965591 fatal user error> kodo.jdo.FatalUserException: Missing table name for field "com.[...].jdo.Branch.branches". This field cannot reside in the owning class table.
at org.apache.openjpa.jdbc.meta.FieldMapping.mapJoin(FieldMapping.java:529)
表格是:
CREATE TABLE branch
(
id VARCHAR2(10) NOT NULL,
parentId VARCHAR2(10) NOT NULL,
[other fields deleted ...]
CONSTRAINT branch_pk PRIMARY KEY(id),
CONSTRAINT branch_fk_parent FOREIGN KEY(parentId) REFERENCES branch(id)
);
班级是:
public class Branch implements MenuPart, Serializable
{
private Branch parent;
private Set<Branch> branches = new HashSet<Branch> ();
private String id;
private Set<Leaf> leafs = new HashSet<Leaf> ();
private long ordering;
private String title;
//methods removed.
}
package.jdo文件是:
<class name="Branch" objectid-class="BranchId" table="SCHEMA.BRANCH">
<version strategy="none"/>
<field name="parent" table="SCHEMA.BRANCH">
<column name="SCHEMA.BRANCH.PARENTID" target="ID" />
</field>
<field name="branches" table="SCHEMA.BRANCH" >
<collection element-type="Branch"/>
<join>
<column name="SCHEMA.BRANCH.PARENTID" target="ID" />
</join>
</field>
<field name="id" column="ID" primary-key="true"/>
<field name="leafs" table="SCHEMA.LEAF">
<collection element-type="Leaf"/>
<join>
<column name="ID" target="BRANCHID" />
</join>
</field>
<field name="ordering" column="ORDERING"/>
<field name="title" column="TITLE"/>
</class>
我已经获得了在kodo jdo 3.4中工作的功能,但现在语法不同了,友好的手册对我来说没那么有用。
答案 0 :(得分:0)
也许它反对你将该关系的连接表定义为类本身的表(这显然是错误的)。
显然,Kodo并不完全符合JDO标准,并且作为一个项目已经死了,所以如果遇到问题那么你就会遇到问题......
答案 1 :(得分:0)
你能试试吗
<class name="Branch" objectid-class="BranchId" table="SCHEMA.BRANCH">
<version strategy="none"/>
<field name="parent" table="SCHEMA.BRANCH">
<column name="SCHEMA.BRANCH.PARENTID" target="ID" />
</field>
<field name="branches" table="SCHEMA.BRANCH" >
<collection element-type="Branch"/>
<extension vendor-name="kodo" key="inverse-owner" value="parent"/>
</field>
<field name="id" column="ID" primary-key="true"/>
</class>
答案 2 :(得分:0)
这是最终起作用的
<class name="Branch" objectid-class="BranchId" table="EBIGP.BRANCH">
<version strategy="none"/>
<field name="parent">
<column name="EBIGP.BRANCH.PARENTID" target="ID" />
</field>
<field name="branches" mapped-by="parent" />
<field name="id" column="ID" primary-key="true"/>
<field name="leafs" default-fetch-group="true">
<collection element-type="Leaf"/>
<element column="BRANCHID"/>
</field>
<field name="ordering" column="ORDERING"/>
<field name="title" column="TITLE"/>
</class>
显然所需要的只是一个 mapped-by =“parent”属性。