我想将SOAP消息发送到Web服务并读取响应。我的代码如下：我将非常感谢您的帮助。
我希望我的问题不会重复，我已经四处寻找解决方案但是我没有成功。
using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.Services;
using System.Xml;
using System.Net;
using System.IO;
namespace TolunaPush
{
public partial class _Default : System.Web.UI.Page
{
private string sourceID = "50001255";
private string email = "adsvine@gmail.com";
private string firstName = "Muz";
private string lastName = "Khan";
private string countryID = "2000077";
private string countryLanguage = "2000240";
private string postalCode = "N19 3NU";
private string dob = "1977-03-08";
private string gender = "2000247";
protected void Page_Load(object sender, EventArgs e)
{
sendSoapMessage();
}
protected void sendSoapMessage()
{
XmlDocument doc = new XmlDocument();
doc.InnerXml = @"<soap:Envelope xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema"" xmlns:soap=""http://schemas.xmlsoap.org/soap/envelope/"">
<soap:Body>
<SubmitPanelist xmlns=""http://www.greenfield.com/RegistrationGateway/Messages"">
<Registration xmlns=""http://www.greenfield.com/RegistrationGateway/Types"">
<Source>
<SourceID>" + sourceID + @"</SourceID>
</Source>
<Email>" + email + @"</Email>
<FirstName>" + firstName + @"</FirstName>
<LastName>" + lastName + @"</LastName>
<CountryUK>
<CountryID>" + countryID + @"</CountryID>
<Language>" + countryLanguage + @"</Language>
<Address>
<Postalcode>" + postalCode + @"</Postalcode>
</Address>
</CountryUK>
<DOB>" + dob + @"</DOB>
<Gender>" + gender + @"</Gender>
</Registration>
</SubmitPanelist>
</soap:Body>
</soap:Envelope>";
HttpWebRequest req = (HttpWebRequest)WebRequest.Create("http://coreg.surveycenter.com/RegistrationGateway/PanelistService.asmx");
//if (proxy != null) req.Proxy = new WebProxy(proxy, true);
// req.Headers.Add("GetClientInfo", "http://tempuri.org/GetClientInfo");
req.ContentType = "text/xml;charset=\"utf-8\"";
req.Accept = "text/xml";
req.Method = "POST";
Stream stm = req.GetRequestStream();
doc.Save(stm);
stm.Close();
WebResponse resp = req.GetResponse();
stm = resp.GetResponseStream();
StreamReader r = new StreamReader(stm);
Response.Write(r.ReadToEnd());
//Response.Write(stm.ToString());
//Response.Write(r.ToString());
Response.End();
}
}
}
更新 正如达林所说。我按照指示做了以下代码行
using (var client = new RegistrationBindingsClient("RegistrationBindings"))
给出错误
The type or namespace name 'RegistrationBindingsClient' could not be found (are you missing a using directive or an assembly reference?)
非常感谢任何帮助
答案 0 :(得分：8)
您尝试使用的Web服务在following address处提供了WSDL。因此，只需右键单击解决方案资源管理器中的“引用”，然后使用Visual Studio中的“添加服务引用”对话框并指向WSDL，它将生成强类型类，以便您轻松使用该服务，如下所示：
protected void sendSoapMessage()
{
using (var client = new RegistrationBindingsClient("RegistrationBindings"))
{
var registration = new RegistrationType();
registration.Source = new SourceType();
registration.Source.SourceID = "50001255";
registration.Email = "adsvine@gmail.com";
registration.FirstName = "Muz";
registration.LastName = "Khan";
var countryUK = new CountryTypeUK();
countryUK.CountryID = 2000077;
countryUK.Language = 2000240;
countryUK.Address = new AddressTypeUK();
countryUK.Address.Postalcode = "N19 3NU";
registration.Item = countryUK;
registration.DOB = new DateTime(1977, 3, 8);
registration.Gender = 2000247;
client.SubmitPanelist(registration);
}
}
看看它有多容易。您不应该担心任何SOAP和XML管道。
如果您对使用此请求在线路上发送的实际基础SOAP信封感兴趣：
<s:Envelope xmlns:s="http://schemas.xmlsoap.org/soap/envelope/">
<s:Body xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<SubmitPanelist xmlns="http://www.greenfield.com/RegistrationGateway/Messages">
<Registration xmlns="http://www.greenfield.com/RegistrationGateway/Types">
<Source>
<SourceID>50001255</SourceID>
</Source>
<Email>adsvine@gmail.com</Email>
<FirstName>Muz</FirstName>
<LastName>Khan</LastName>
<CountryUK>
<CountryID>2000077</CountryID>
<Language>2000240</Language>
<Income>0</Income>
<Education>0</Education>
<Address>
<Postalcode>N19 3NU</Postalcode>
</Address>
</CountryUK>
<DOB>1977-03-08</DOB>
<Gender>2000247</Gender>
</Registration>
</SubmitPanelist>
</s:Body>
</s:Envelope>
答案 1 :(得分：0)
是否有任何错误消息或您是否使用HTTP监视器？
一些可能有用的链接：
答案 2 :(得分：0)
您可以通过两种方式访问该服务：
添加服务的Web引用。在visual studio中，您可以右键单击项目并选择Add Web reference选项，然后粘贴服务的URL。
使用Visual Studio命令提示符下的wsdl工具从wsdl生成客户端代理。命令如下：
c：＆gt; wsdl“http://coreg.surveycenter.com/RegistrationGateway/PanelistService.asmx?wsdl
它将生成.cs文件和output.config。在项目中包含.cs文件，您可以直接使用它来访问该服务。确保将配置文件条目添加到项目配置中。
如果您想使用HttpWebRequest，请找到以下代码：
string soap =
@"<?xml version=""1.0"" encoding=""utf-8""?>
<soap:Envelope xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance""
xmlns:xsd=""http://www.w3.org/2001/XMLSchema""
xmlns:soap=""http://schemas.xmlsoap.org/soap/envelope/"">
<soap:Body>
<Register xmlns=""http://tempuri.org/"">
<id>123</id>
<data1>string</data1>
</Register>
</soap:Body>
</soap:Envelope>";
HttpWebRequest req = (HttpWebRequest)WebRequest.Create("http://localhost/WebServices/CustomerWebService.asmx");
req.Headers.Add("SOAPAction", "\"http://tempuri.org/Register\"");
req.ContentType = "text/xml;charset=\"utf-8\"";
req.Accept = "text/xml";
req.Method = "POST";
using (Stream stm = req.GetRequestStream())
{
using (StreamWriter stmw = new StreamWriter(stm))
{
stmw.Write(soap);
}
}
WebResponse response = req.GetResponse();
Stream responseStream = response.GetResponseStream();
// TODO: Do whatever you need with the response
我的服务如下：
[WebService(Namespace = "http://tempuri.org/")]
[WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)]
public class CustomerWebService : System.Web.Services.WebService
{
[WebMethod]
public string Register(long id, string data1)
{
return "ID.CUSTOMER";
}
}
答案 3 :(得分：0)
这是一个通用课程，您可以用它来实现您的需要。
重要免责声明：您只应在需要（或需要）手动发布基于SOAP的Web服务时使用此功能：在大多数常见情况下，您绝对应该将Web服务WSDL与添加服务参考 Visual Studio功能，这是正确的方法。
using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Net;
using System.Xml;
namespace Ryadel.Web.SOAP
{
/// <summary>
/// Helper class to send custom SOAP requests.
/// </summary>
public static class SOAPHelper
{
/// <summary>
/// Sends a custom sync SOAP request to given URL and receive a request
/// </summary>
/// <param name="url">The WebService endpoint URL</param>
/// <param name="action">The WebService action name</param>
/// <param name="parameters">A dictionary containing the parameters in a key-value fashion</param>
/// <param name="soapAction">The SOAPAction value, as specified in the Web Service's WSDL (or NULL to use the url parameter)</param>
/// <param name="useSOAP12">Set this to TRUE to use the SOAP v1.2 protocol, FALSE to use the SOAP v1.1 (default)</param>
/// <returns>A string containing the raw Web Service response</returns>
public static string SendSOAPRequest(string url, string action, Dictionary<string, string> parameters, string soapAction = null, bool useSOAP12 = false)
{
// Create the SOAP envelope
XmlDocument soapEnvelopeXml = new XmlDocument();
var xmlStr = (useSOAP12)
? @"<?xml version=""1.0"" encoding=""utf-8""?>
<soap12:Envelope xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance""
xmlns:xsd=""http://www.w3.org/2001/XMLSchema""
xmlns:soap12=""http://www.w3.org/2003/05/soap-envelope"">
<soap12:Body>
<{0} xmlns=""{1}"">{2}</{0}>
</soap12:Body>
</soap12:Envelope>"
: @"<?xml version=""1.0"" encoding=""utf-8""?>
<soap:Envelope xmlns:soap=""http://schemas.xmlsoap.org/soap/envelope/""
xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance""
xmlns:xsd=""http://www.w3.org/2001/XMLSchema"">
<soap:Body>
<{0} xmlns=""{1}"">{2}</{0}>
</soap:Body>
</soap:Envelope>";
string parms = string.Join(string.Empty, parameters.Select(kv => String.Format("<{0}>{1}</{0}>", kv.Key, kv.Value)).ToArray());
var s = String.Format(xmlStr, action, new Uri(url).GetLeftPart(UriPartial.Authority) + "/", parms);
soapEnvelopeXml.LoadXml(s);
// Create the web request
HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(url);
webRequest.Headers.Add("SOAPAction", soapAction ?? url);
webRequest.ContentType = (useSOAP12) ? "application/soap+xml;charset=\"utf-8\"" : "text/xml;charset=\"utf-8\"";
webRequest.Accept = (useSOAP12) ? "application/soap+xml" : "text/xml";
webRequest.Method = "POST";
// Insert SOAP envelope
using (Stream stream = webRequest.GetRequestStream())
{
soapEnvelopeXml.Save(stream);
}
// Send request and retrieve result
string result;
using (WebResponse response = webRequest.GetResponse())
{
using (StreamReader rd = new StreamReader(response.GetResponseStream()))
{
result = rd.ReadToEnd();
}
}
return result;
}
}
}
了解更多信息＆amp;有关此课程的详细信息，您也可以在我的博客上read this post。