Question

我一直在阅读使用Ajnd和Jquery和Zend，但我似乎无法理解这个想法。例如，我有一个带有一些注释的简单帖子，我希望在不需要刷新的情况下向页面发表评论。

这就是我所拥有的：

 //Controller


 public function viewAction()
{
   // action body
    $postid = $this->_getParam('id', 0);
    $post = new Application_Model_DbTable_Videos(); 
    $this->view->post = $post->getVideos($postid);
    $commentsObj = new Application_Model_DbTable_Comments();
    $request = $this->getRequest();
    $commentsForm = new Application_Form_Comments();
    /*
     * Check the comment form has been posted
     */
    if ($this->getRequest()->isPost()) {
        if ($commentsForm->isValid($request->getPost())) {
            $model = new Application_Model_DbTable_Comments();
            $model->saveComments($commentsForm->getValues());
            $commentsForm->reset();
        }
    }
    $data = array( 'id'=> $postid );
    $commentsForm->populate( $data );
    $this->view->commentsForm = $commentsForm;
    $comments = $commentsObj->getComments($postid);
    $this->view->comments = $comments;
    $this->view->edit = '/videos/edit/id/'.$postid;
}

//View

    <?php echo $this->post['Title']; ?><br>
   <?php echo $this->post['Description'];  ?><br><br>

<?php if( count($this->comments) ) : ?>
    <?php foreach( $this->comments as $comment ) : ?>
        <a href="<?php echo $comment['Webpage']; ?>" ><?php echo $this->escape( $comment['Name'] ); ?></a> on <span>
        <?php echo $this->escape( date( 'd-m-Y', strtotime($comment['Postedon']) ) ); ?></span><br><br>
        <?php echo $this->escape( $comment['Description'] ); ?><br>
    <?php endforeach; ?>
<?php else : ?>
<div>No comments</div><br>
<?php endif; ?>
    <br>
    <?php echo $this->commentsForm; ?>

请指导我某个方向，因为我花了很多时间没有运气:(

尝试更新：

//View file
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
    $('submitbutton').click(function(){
          var comments = $('comment').val();
         $.ajax({
         url : 'localhost/kiwi/public/videos/addcomment',
         type : 'POST',
         data : {'commments_post':comments },
         success:function(msg){ 
             if(msg=='Ok'){
             alert('You have saved the comment with out refresh');
               }else{
             alert('cant save');
               }
         },
         error:function()
         {
             alert('Error');
         }
      });
});
});
</script>

<?php echo $this->post['Title']; ?><br>
<?php echo $this->post['Description'];  ?><br><br>

<?php if( count($this->comments) ) : ?>
    <?php foreach( $this->comments as $comment ) : ?>
        <a href="<?php echo $comment['Webpage']; ?>" ><?php echo $this->escape( $comment['Name'] ); ?></a> on <span>
        <?php echo $this->escape( date( 'd-m-Y', strtotime($comment['Postedon']) ) ); ?></span><br><br>
        <?php echo $this->escape( $comment['Description'] ); ?><br>
    <?php endforeach; ?>
<?php else : ?>
<div>No comments</div><br>
<?php endif; ?>
<br>
<?php echo $this->commentsForm; ?>

我的控制员：

 public function viewAction()
{
   // action body
    $postid = $this->_getParam('id', 0);
    $post = new Application_Model_DbTable_Videos(); 
    $this->view->post = $post->getVideos($postid);
    $commentsObj = new Application_Model_DbTable_Comments();
    $commentsForm = new Application_Form_Comments();

    $data = array( 'id'=> $postid );
    $commentsForm->populate( $data );
    $this->view->commentsForm = $commentsForm;
    $comments = $commentsObj->getComments($postid);
    $this->view->comments = $comments;
}

public function addcommentAction()
{

    $request = $this->getRequest();
    $commentsForm = new Application_Form_Comments();
    $commentsObj = new Application_Model_DbTable_Comments();

    if ($this->getRequest()->isPost()) {
        if ($commentsForm->isValid($request->getPost())) {
            $model = new Application_Model_DbTable_Comments();
            $model->saveComments($commentsForm->getValues());
            $commentsForm->reset();
        }
    }


}

Answer 1

视图操作不应包含添加注释的方法。而是做出addcoment动作。然后，表格包含新闻或任何内容以及评论的ID。您通过ajax发送了表单，由于$this->getRequest()->isXmlHttpRequest()，您可以检查帖子是来自ajax还是手动添加witihout javascript。

根据您返回成功和错误的json回调。你不仅要回馈'成功'，而且你也可以回复json中添加的评论。

jQuery处理剩下的事情。正确格式化评论，将其添加到您的DOM和中提琴。评论补充说。

作为一点指导，这应该足够了，如果你想要上述任何一个的具体信息，请给我发表评论，然后进一步编辑我的答案;）

Answer 2

这样做，

    $(document).ready(function(){
        $('#your_comment_save_button_id').click(function(){
              var comments = $('#commentbox_id').val();
             $.ajax({
             url : 'Your comment save page url',
             type : 'POST',
             data : {'commments_post':comments },
             success:function(msg){ //msg a variable echoed from the save page
                 if(msg=='Ok'){
                 alert('You have saved the comment with out refresh');
                   }else{
                 alert('cant save');
                   }
             },
             error:function()
             {
                 alert('Error');
             }
          });
    });
    });

Zend Framework，用ajax和jquery发表评论

2 个答案: