我的查询速度很慢。我知道使用依赖子查询是不好的,但我想不出另一种方法来获取我想要的数据。
基本上,我想标记过去6个月内至少有50张发票的客户,但本月没有发票。
这就是我目前的情况:
select
Customer.name,
Customer.id,
Customer.latitude,
Customer.longitude
from
Customer
where
EXISTS (
SELECT
*
FROM
Invoice_Header
WHERE
Invoice_Header.inv_date BETWEEN '2011-03-02' AND '2011-10-02'
AND
Invoice_Header.account_number = Customer.account_number
HAVING COUNT(invoice_num) > 50
)
AND NOT EXISTS (
SELECT *
FROM
Invoice_Header
WHERE
InvHead.inv_date > '2011-10-02'
AND
InvHead.account_number = Customer.account_number
)
Group by name;
客户表约有12k记录,Invoice_Header约有2,500条记录。
我在inv_date,account_number(两个表中)都有索引。
对于如何提高速度的任何建议都将不胜感激。
答案 0 :(得分:3)
这应该消除相关的子查询并且明显更快:
SELECT c.name, c.id, c.latitude, c.longitude
FROM Customer c
INNER JOIN (
SELECT account_number
FROM Invoice_Header ih
WHERE ih.inv_date BETWEEN '2011-03-02' AND '2011-10-02'
GROUP BY account_number
HAVING COUNT(*) > 50
MINUS
SELECT DISTINCT account_number
FROM Invoice_Header ih
WHERE ih.inv_date > '2011-10-02'
) tbl
ON tbl.account_number = c.account_number
答案 1 :(得分:2)
select
C.name,
C.id,
C.latitude,
C.longitude,
I.account_number,
count( IF(I.inv_date>='2011-03-02' AND I.inv_date <='2011-10-02',I.inv_date,NULL )) as inv_count_6,
count( IF(I.inv_date > '2011-10-02',I.inv_date,NULL )) as inv_count_1
from Customer C
LEFT JOIN Invoice_Header I
ON C.account_number = I.account_number
GROUP BY C.id, I.account_number
HAVING inv_count_6 >= 50 AND inv_count_1=0
WHERE I.inv_date BETWEEN '2011-03-02' AND '2011-10-02'
注意:
1.发票至少为50.所以条件是> = 50不是> 50。
2.您必须将索引添加到列inv_date
答案 2 :(得分:2)
我建议:
SELECT
c.name,
c.id,
c.latitude,
c.longitude
FROM
Customer AS c
INNER JOIN (
SELECT account_number, count(*) AS invoice_count
FROM Invoice_Header
WHERE inv_date >= '2011-03-02' AND inv_date <= '2011-10-02'
GROUP BY account_number
) AS lsm
ON c.account_number = lsm.account_number
LEFT JOIN (
SELECT account_number, count(*) AS invoice_count
FROM Invoice_Header
WHERE inv_date > '2011-10-02'
GROUP BY account_number
) AS lm
ON c.account_number = lm.account_number
WHERE
lsm.invoice_count >= 50
AND IFNULL(lm.invoice_count, 0) = 0
答案 3 :(得分:1)
尝试使用explain运行查询,并查看是否需要其他索引。