Question

我有一个带有以下结构和数据的SQL查询结果

ProductId #date      #customercode  # SomeIndex    # SomeIndexvalue
13       2011-10-01     1           A1              9397062 
14       2011-10-01     2           A1              3575045 
15       2011-10-01     3           A1             3575321  
13       2011-10-01     1           A2             1318774
14       2011-10-01     2           A2             838924
15       2011-10-01     3           A2             8942430

在此索引值中，productid，date，customercode是唯一的。现在我需要将SomeIndex设为列，以便在给定数据中只有三行。即，以下结构

ProductId #date      #customercode  # A1      # A2
13       2011-10-01     1           9397062   1318774
14       2011-10-01     2           3575045   838924
15       2011-10-01     3           3575321   8942430

我正在使用sqlserver 2008.任何人都可以帮助我。在此先感谢大家

Answer 1

SELECT ProductId, [#date], [#customercode],
       MIN(CASE WHEN [#SomeIndex] = 'A1' THEN [#SomeIndexvalue] END) [#A1],
       MIN(CASE WHEN [#SomeIndex] = 'A2' THEN [#SomeIndexvalue] END) [#A2]
FROM YourTable
GROUP BY ProductId, [#date], [#customercode]

Answer 2

使用PIVOT运算符（SQL 2008版本）

create table #test(
ProductId int,
dt date,
customercode int,
someindex varchar(255),
SomeIndexvalue int
)

insert into #test values
(13,'2011-10-01',1,'A1',9397062),
(14,'2011-10-01',2,'A1',3575045),
(15,'2011-10-01',3,'A1',3575321),
(13,'2011-10-01',1,'A2',1318774),
(14,'2011-10-01',2,'A2',838924),
(15,'2011-10-01',3,'A2',8942430)


select * from 
(
   select 
      * 
   from  
      #test
)DATA_TO_PIVOT
PIVOT
(
MAX(SomeIndexvalue) for someindex in ([A1],[A2])
)PIVOTED_DATA

将行组更改为列

2 个答案: