将嵌套的XML加载到数据集中

时间:2009-04-17 06:20:25

标签: c# xml dataset

如何将以下嵌套XML加载到DataSet中?

<items>
  <item>
   <id>i1</id>
   <name>item1</name>
   <subitems>
    <name>subitem1</name>
    <name>subitem2</name>
   </subitems>
  </item>
  <item>
   <id>i2</id>
   <name>item2</name>
   <subitems>
    <name>subitem1</name>
    <name>subitem2</name>
   </subitems>
  </item>
 </items>

我可以获得“项目”表格,但我如何获得子项目?

 MemoryStream itemsStream = new MemoryStream(Encoding.ASCII.GetBytes(itemsXML));
 DataSet itemsSet = new DataSet();
 itemsSet.ReadXml(itemsStream);
 foreach (DataRow itemRow in itemsSet.Tables["item"].Rows) {
     Console.WriteLine("column id=" + itemRow["id"] as string + " name=" + itemRow["name"] as string);
 }

3 个答案:

答案 0 :(得分:2)

这对我有用,我所采取的唯一自由是更改子项目的字段名称。

subitem的原始XML

   <subitems>
     <name>subitem1</name>
     <name>subitem2</name>
   </subitems>

修改了子项目的XML

   <subitems>
       <name1>subitem1</name1>
       <name2>subitem2</name2>
   </subitems>

这是代码。

        DataSet myDS = new DataSet();
        DataTable myTable = new DataTable("item");
        myTable.Columns.Add("id", typeof(string));
        myTable.Columns.Add("name", typeof(string));
        myTable.Columns.Add("name1", typeof(string));
        myTable.Columns.Add("name2", typeof(string));

        myDS.Tables.Add(myTable);

        string xmlData = "<items>  <item>   <id>i1</id>   <name>item1</name>   <subitems>    <name1>subitem1</name1>    <name2>subitem2</name2>   </subitems>  </item>  <item>   <id>i2</id>   <name>item2</name>   <subitems>    <name1>subitem3</name1>    <name2>subitem4</name2>   </subitems></item></items>";
        System.IO.MemoryStream itemsStream = new System.IO.MemoryStream(Encoding.ASCII.GetBytes(xmlData));

        myDS.ReadXml(itemsStream, XmlReadMode.IgnoreSchema);
        foreach (DataRow itemRow in myDS.Tables["item"].Rows)
        {
            MessageBox.Show("column id=" + itemRow["id"]  + " name=" + itemRow["name"]);
            MessageBox.Show(itemRow["name1"].ToString() + " - " + itemRow["name2"].ToString());
        }

答案 1 :(得分:0)

使用数据集ReadXml。你必须在下面的链接上关注文章:

http://msdn.microsoft.com/en-us/library/7sfkwf9s(v=VS.100).aspx

For Instance:

DataSet ds = new DataSet();
ds.ReadXml(new StringReader(nestedXml));
StringBuilder sb = new StringBuilder();
ds.WriteXml(new StringWriter(sb));
Response.Write(sb.ToString());

当然,您可以使用ds.Tables[0]ds.Tables[1]

分别阅读表格

答案 2 :(得分:0)

String sss = @"<items>
<item>
  <id>i1</id>
   <name>item1</name>
    <subitems>
     <name>subitem1</name>
     <name>subitem2</name>
    </subitems>
   </item>
   <item>
    <id>i2</id>
     <name>item2</name>
      <subitems>
       <name>subitem1</name>
       <name>subitem2</name>
      </subitems>
     </item>
    </items>";

StringReader rr = new StringReader(sss);
DataSet sdread = new DataSet();
sdread.ReadXml(rr);