我正在尝试将Android XML的外观与以编程方式创建它的方式相关联,而且我的失败很糟糕。我已经阅读了几个引用,声明View的LayoutParams的类型必须等于父类的类型,但我只是不想它。
鉴于以下XML,我将如何以编程方式重新创建它?
<TableRow
android:layout_height="fill_parent"
android:layout_width="fill_parent"
android:layout_gravity="center_vertical"
>
<LinearLayout
android:layout_height="wrap_content"
android:layout_width="fill_parent"
android:layout_gravity="center_vertical"
android:paddingTop="3dp"
android:orientation="vertical"
>
<EditText
android:padding="2dp"
android:layout_width="100dp"
android:layout_height="35dp"
android:layout_column="0"
android:layout_weight="1"
android:layout_gravity="center_vertical"
android:textSize="15dp"
android:numeric="integer"
/>
</LinearLayout>
<LinearLayout
android:layout_height="35dp"
android:layout_width="fill_parent"
android:layout_weight="1"
android:layout_gravity="center_vertical"
android:padding="2dp"
android:orientation="vertical"
>
<CheckBox android:text="Check1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_weight="1"
android:textSize="10sp"
android:background="@drawable/checkbox_background"
android:button="@drawable/checkbox"
android:textColor="@color/Gray"
/>
<CheckBox android:text="Check2"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_weight="1"
android:textSize="10sp"
android:background="@drawable/checkbox_background"
android:button="@drawable/checkbox"
android:textColor="@color/Gray"
/>
</LinearLayout>
这是我尝试过的:
// Get the TableLayout
TableLayout tl = (TableLayout)findViewById(R.id.score_table);
LayoutParams lp;
TableRow.LayoutParams tp;
// Create a TableRow and give it an ID
TableRow tr = new TableRow(this);
tr.setId(100);
tr.setLayoutParams(new TableRow.LayoutParams(
LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT));
LinearLayout ll0_1 = new LinearLayout(this);
// If the layout params of the child should be of
// the type of the parent this should be
// TableRow.LayoutParams?
tp = (TableRow.LayoutParams)tr.getLayoutParams();
tp.height = TableRow.LayoutParams.WRAP_CONTENT;
tp.width = TableRow.LayoutParams.FILL_PARENT;
tp.gravity = Gravity.CENTER_VERTICAL;
// TableRow.LayoutParams has no padding so this
// gets set on the LinearLayout?
ll0_1.setPadding(0,3,0,0);
ll0_1.setLayoutParams(tp);
tr.addView(ll0_1);
EditText et0 = new EditText(this);
et0.setId(100);
et0.setInputType(InputType.TYPE_CLASS_NUMBER);
// Same as above; LP set to type of parent
lp = new LinearLayout.LayoutParams(LayoutParams.FILL_PARENT,
LayoutParams.WRAP_CONTENT, 1f);
lp.height = 35;
lp.width = 100;
// Same as above; the parent's type doesn't have
// these attributes
et0.setTextSize(TypedValue.COMPLEX_UNIT_SP, 15);
et0.setPadding(0, 3, 0, 0);
et0.setLayoutParams(lp);
ll0_1.addView(et0);
LinearLayout ll0_2 = new LinearLayout(this);
ll0_2.setOrientation(LinearLayout.VERTICAL);
tr.addView(ll0_2);
CheckBox cb0_1 = new CheckBox(this);
cb0_1.setTextSize(10f);
cb0_1.setTextColor(Color.GRAY);
cb0_1.setBackgroundResource(R.drawable.checkbox_background);
cb0_1.setButtonDrawable(R.drawable.checkbox);
cb0_1.setText("Nil");
ll0_2.addView(cb0_1);
CheckBox cb0_2 = new CheckBox(this);
cb0_2.setTextSize(10f);
cb0_2.setTextColor(Color.GRAY);
cb0_2.setBackgroundResource(R.drawable.checkbox_background);
cb0_2.setButtonDrawable(R.drawable.checkbox);
cb0_2.setText("10fer");
ll0_2.addView(cb0_2);
// Duplicate code removed for brevity
//...
// Add the TableRow to the TableLayout
tl.addView(tr, new TableLayout.LayoutParams(
LayoutParams.FILL_PARENT, LayoutParams.FILL_PARENT));
没有错误,但它与XML不匹配。相反,它看起来像这样:
第一个来自XML,第二个是我尝试以编程方式再现它。
答案 0 :(得分:1)
LayoutInflater是最简单的方法:
public View myView(){
View v;
LayoutInflater inflater = (LayoutInflater)getBaseContext().getSystemService(Context.LAYOUT_INFLATER_SERVICE);
v = inflater.inflate(R.layout.myview, null);
TextView text1 = (TextView) v.findViewById(R.id.dolphinTitle);
Button btn1 = (Button) v.findViewById(R.id.dolphinMinusButton);
TextView text2 = (TextView) v.findViewById(R.id. dolphinValue);
Button btn2 = (Button) v.findViewById(R.id. dolphinPlusButton);
return v;
}