我正在运行以下查询:
SELECT ol.name, o.email AS email, o.phone AS phone, MAX(nrs.created) AS last_subscription, nlf.name AS `neighborhood_name`
FROM organisation AS o
LEFT OUTER JOIN organisation_localisation_fallback AS ol ON o.id = ol.organisation_id and ol.language_id=14 and ol.country_id=19
LEFT JOIN neighborhood_request_subscription AS nrs ON o.id = nrs.from_organisation_id
LEFT JOIN organisation_neighborhood AS orgn ON o.id = orgn.organisation_id
LEFT OUTER JOIN neighborhood_localisation_fallback AS nlf ON orgn.neighborhood_id = nlf.neighborhood_id AND nlf.language_id=14 AND nlf.country_id=19
WHERE o.id IN (73)
GROUP BY o.id
ORDER BY nrs.created IS NOT NULL, nrs.created ASC
结果给了我以下列:
<块引用>姓名 |电子邮件 |电话 | last_subscription |姓名
我尝试将列更改为:
neighborhood_name
(带反引号)以上都不起作用,他们一直给我回“name”作为列名。 在上面的查询中,我也无法更改第一列“ol.name”的别名。
答案 0 :(得分:0)
我通过使用 CONCAT 设法克服了这个问题,如下所示:
CONCAT(nlf.name, '') AS neighborhood_name