[编辑 1]

Question

我在 s3 存储桶的文件夹中有一个压缩文件。我想使用 boto3 解压缩文件。到目前为止，这是我的代码。

def unzip_file(path, file_name):
    s3 = boto3.resource('s3', aws_access_key_id=ACCESS_KEY, aws_secret_access_key=SECRET_KEY)
    my_bucket = s3.Bucket(BUCKET)

    lst = list(my_bucket.objects.filter(Prefix=path))
    unzip_path = '/'.join(str(lst[0].key).split('/')[:-1])

    with zipfile.ZipFile(f"{path}/{file_name}", 'r') as zip_ref:
        zip_ref.extractall(unzip_path)

但这只是给出如下错误

Traceback (most recent call last):
  File "download.py", line 153, in <module>
    unzip_file(path, file_name)
  File "download.py", line 32, in unzip_file
    with zipfile.ZipFile(f"{path}/{file_name}", 'r') as zip_ref:
  File "/Users/sashaanksekar/anaconda3/lib/python3.8/zipfile.py", line 1250, in __init__
    self.fp = io.open(file, filemode)
FileNotFoundError: [Errno 2] No such file or directory: 'test_parent/test_num/test.zip'

如何使用 python 和 boto3 解压文件？

[编辑 1]

我已经编辑了代码，压缩文件现在在内存中。如何将所有文件提取到 S3 中。

这是我的代码

def unzip_file(r, path, file_name):
    s3 = boto3.resource('s3', aws_access_key_id=ACCESS_KEY, aws_secret_access_key=SECRET_KEY)
    my_bucket = s3.Bucket(BUCKET)

    if r.status_code == 200:
        filebytes = BytesIO(r.content)
        file = zipfile.ZipFile(filebytes)

        extract_folder = f"{path}extract_test/"
        
        # extract each file in file.namelist() and save in extract_folder here

Answer 1

由于我不确定 public static List<GetProducts_Result> CreateFromReader(DbDataReader reader) { List<GetProducts_Result> result = new List<GetProducts_Result>(); while (reader.Read()) { result.Add(new GetProducts_Result { Name = reader.GetString(reader.GetOrdinal("Name")), Brand = reader.GetString(reader.GetOrdinal("Brand")), ... // read remaining fields } return result; } 是什么以及函数背后的逻辑，我提供了一个工作示例：

r.content

如何在 s3 中解压缩压缩文件

[编辑 1]

1 个答案: