报告的SQL查询产生错误的结果

Question

我有关于sql的这个问题我将在web服务中使用，如果我能做到这一点。我想要做的是创建一个事务的摘要报告。该交易有标题和行。在交易中，我们将输入许多木板。

在输入之后，我想制作一份报告，将添加属于某一类别的所有木板，然后将所有木板乘以该供应商的价格，以便我可以获得总金额。这是一张图片：

下面是我的sql产生了错误的输出：

select
      t1.transaction_num,
      wo1.wood_classification_desc,
      wo2.wood_specie_desc,
      sum(t2.board_foot) as total_board_foot,
      su1.price,
      sum(t2.board_foot*su1.price) as total_amount
    from
      "transaction_hdr" t1
      left join "transaction_lne" t2 on (t1.transaction_id = t2.transaction_id)
      left join "supplier" su2 on (t1.supplier_id = su2.supplier_id)
      left join "supplier_price" su1 on (t2.price = su1.price)
      left join "wood_classification" wo1 on (t2.wood_classification_id = wo1.wood_classification_id)
      left join "wood_specie" wo2 on (wo1.wood_specie_id = wo2.wood_specie_id)
    group by
      t1.transaction_num,wo1.wood_classification_desc,su1.price,su2.supplier_name,wo2.wood_specie_desc
    order by transaction_num,wo2.wood_specie_desc

Evrytime我运行那个sql，它产生这样的东西：

我测试的交易只有五个木板。 Mahogany 6" wider - 7ft. up和1 Mahogany 5" wider - 7ft. up下的4个木板。

Answer 1

我猜，在其中一个左连接中你有多个记录，这意味着它会给你错误的总和（分组将影响左连接后的设置）。

只需运行没有分组的sql并检查你得到了什么。

所以它可能不是导致问题的乘法，而是总和。

Answer 2

您在supplier_price中有多个记录，价格= 13.33吗？这是我的猜测，因为所有其他连接似乎都在主键上..

编辑：

您的问题是您在价格字段上加入supplier_price，这不是有效密钥。鉴于您的输出没有从supplier_price表中获取任何内容，我倾向于将其从查询中删除，如下所示：

select
      t1.transaction_num,
      wo1.wood_classification_desc,
      wo2.wood_specie_desc,
      sum(t2.board_foot) as total_board_foot,
      t2.price,
      sum(t2.board_foot*t2.price) as total_amount
    from
      "transaction_hdr" t1
      left join "transaction_lne" t2 on (t1.transaction_id = t2.transaction_id)
      left join "supplier" su2 on (t1.supplier_id = su2.supplier_id)
      left join "wood_classification" wo1 on (t2.wood_classification_id = wo1.wood_classification_id)
      left join "wood_specie" wo2 on (wo1.wood_specie_id = wo2.wood_specie_id)
    group by
      t1.transaction_num,wo1.wood_classification_desc,t2.price,su2.supplier_name,wo2.wood_specie_desc
    order by transaction_num,wo2.wood_specie_desc

Answer 3

这可能会解决问题。但是如果你提供了表（和表的主键）之间的关系，它会有所帮助：

select
      t1.transaction_num,
      wo1.wood_classification_desc,
      wo2.wood_specie_desc,
      sum(t2.board_foot)
        as total_board_foot,
      ( SELECT DISTINCT su1.price
        FROM "supplier_price" su1
        WHERE t2.price = su1.price
      ) AS price,
      sum(t2.board_foot) *
          ( SELECT DISTINCT su1.price
            FROM "supplier_price" su1
            WHERE t2.price = su1.price
          )
        as total_amount
    from
      "transaction_hdr" t1
      left join "transaction_lne" t2
        on (t1.transaction_id = t2.transaction_id)
      left join "supplier" su2 
        on (t1.supplier_id = su2.supplier_id)
      left join "wood_classification" wo1
        on (t2.wood_classification_id = wo1.wood_classification_id)
      left join "wood_specie" wo2
        on (wo1.wood_specie_id = wo2.wood_specie_id)
    group by
        t1.transaction_num
      , wo1.wood_classification_desc
      , su2.supplier_name
      , wo2.wood_specie_desc
    order by transaction_num
           , wo2.wood_specie_desc