我想要一个表格,我可以在其中将今天的余额和昨天的余额视为两个不同的列。有什么办法可以从两个不同的日期中进行选择吗?
以下是我尝试过的 SQL 语句,但是我看不到昨天的余额。
(SELECT food.food_id, food.food_name, food.food_chi_name, food.food_category, food.chinesechar, SUM(inventory.tmr_input+inventory.final_balance), SUM(inventory.balance), SUM(inventory.input), SUM(inventory.reject), SUM(inventory.final_balance), SUM(inventory.tmr_input), SUM(inventory.sale), SUM(inventory.theoritical), SUM(inventory.yest_theoritical), SUM(inventory.3PMsale), SUM(inventory.3PMbalance), SUM(inventory.wholesale) FROM inventory INNER JOIN food ON inventory.food_id=food.food_id WHERE food.outlet = 'T11' AND inventory.date = '04/30/2021' GROUP BY food.food_id ORDER BY food.food_id ASC); (SELECT SUM(inventory.balance) as yesterday_balance FROM inventory INNER JOIN food ON inventory.food_id=food.food_id WHERE food.outlet = 'T11' AND inventory.date = '04/29/2021' GROUP BY food.food_id ORDER BY food.food_id ASC);
答案 0 :(得分:0)
您可以为此使用子选择
使用别名有助于获得更好的概览
SELECT
f1.food_id
, f1.food_name
, f1.food_chi_name
, f1.food_category
, f1.chinesechar
, SUM(i1.tmr_input+i1.final_balance)
, SUM(i1.balance)
, SUM(i1.input)
, SUM(i1.reject)
,SUM(i1.final_balance)
, SUM(i1.tmr_input)
, SUM(i1.sale)
, SUM(i1.theoritical)
, SUM(i1.yest_theoritical)
, SUM(i1.`3PMsale`)
, SUM(i1.`3PMbalance`)
, SUM(i1.wholesale)
,(SELECT SUM(i2.balance)
FROM
inventory i2 INNER JOIN food f2 ON i2.food_id=f2.food_id
WHERE f2.outlet = 'T11' AND i2.date = '04/29/2021'
AND f2.food_id = f1.food_id
) as yesterday_balance
FROM
inventory i1
INNER JOIN
food f1 ON i1.food_id=f1.food_id
WHERE
f1.outlet = 'T11'
AND i1.date = '04/30/2021'
GROUP BY f1.food_id
ORDER BY f1.food_id ASC;