我正在尝试将两个 sql 查询的结果合并为一个
查询 1:
SELECT COUNT(class) as show, year
FROM lee
where class = 'Show'
GROUP BY year
结果
show year
185 2016
296 2020
655 2019
查询 2
SELECT COUNT(class) as movie, year
FROM lee
where class = 'movie'
GROUP BY year
结果
movie year
556 2016
987 2020
690 2019
我如何实现这样的目标:
movie show year
556 185 2016
987 296 2020
690 655 2019
答案 0 :(得分:1)
您可以使用 case when
语句选择计数类。
SELECT count(CASE WHEN class = 'movie' THEN 1 END) as movie,
count(CASE WHEN class = 'show' THEN 1 END) as show,
year
FROM lee
GROUP BY year;
答案 1 :(得分:0)
使用条件聚合:
SELECT SUM(CASE WHEN class = 'show' THEN 1 ELSE 0 END) as show,
SUM(CASE WHEN class = 'movie' THEN 1 ELSE 0 END) as movie,
year
FROM lee
GROUP BY year;
答案 2 :(得分:0)
我的解决方案不是最漂亮的,但它是给另一个选择
SELECT m.movie, s.show, m.YEAR FROM
(SELECT COUNT(1) AS movie, YEAR FROM LEE WHERE CLASS = 'movie' GROUP BY YEAR) m
JOIN (SELECT COUNT(1) AS show, YEAR FROM LEE WHERE CLASS = 'show' GROUP BY YEAR) s
ON (s.YEAR = m.YEAR);