我有两个查询如下:
Expr1 | SumOfBRK |
---|---|
08/03/2021 | 32499 |
09/03/2021 | 2687 |
28/02/2021 | 355 |
SELECT Format([TBL_BRK_DATA_OUTPUT].[DATE],"Short Date") AS Expr1, Sum(TBL_BRK_DATA_OUTPUT.QUANTITY) AS SumOfBRK FROM TBL_BRK_DATA_OUTPUT GROUP BY Format([TBL_BRK_DATA_OUTPUT].[DATE],"Short Date");
Expr1 | SumOfSTD |
---|---|
08/03/2021 | 6178 |
09/03/2021 | 4135 |
28/02/2021 | 2845 |
SELECT Format([TBL_STD_DATA_OUTPUT].[DATE],"Short Date") AS Expr1, Sum(TBL_STD_DATA_OUTPUT.QUANTITY) AS SumOfSTD FROM TBL_STD_DATA_OUTPUT GROUP BY Format([TBL_STD_DATA_OUTPUT].[DATE],"Short Date");
我希望结果如下:
Expr1 | SumOfSTD | SumOfBRK |
---|---|---|
08/03/2021 | 6178 | 32499 |
09/03/2021 | 4135 | 2687 |
28/02/2021 | 2845 | 355 |
谁能帮帮我?我尝试使用联合来组合它们,但结果不是我所期望的
谢谢。
博斯科
答案 0 :(得分:0)
听起来你想要一个加入,而不是联合:
SELECT t1.Expr1, t2.SumOfSTD, t1.SumOfBRK
FROM
(
SELECT FORMAT([TBL_BRK_DATA_OUTPUT].[DATE], "Short Date") AS Expr1,
SUM(TBL_BRK_DATA_OUTPUT.QUANTITY) AS SumOfBRK
FROM TBL_BRK_DATA_OUTPUT
GROUP BY FORMAT([TBL_BRK_DATA_OUTPUT].[DATE], "Short Date")
) t1
INNER JOIN
(
SELECT FORMAT([TBL_STD_DATA_OUTPUT].[DATE], "Short Date") AS Expr1,
SUM(TBL_STD_DATA_OUTPUT.QUANTITY) AS SumOfSTD
FROM TBL_STD_DATA_OUTPUT
GROUP BY FORMAT[TBL_STD_DATA_OUTPUT].[DATE], "Short Date")
) t2
ON t2.Expr1 = t1.Expr1;