Question

我有一组似乎不起作用的PDO语句。基本上我试图更新1表中的“等待”值，然后选择相同的行并将其插入另一个表。

$statement = $db->prepare("UPDATE waiting SET wait = :status WHERE id = :id");
$statement->bindValue(':status', 0);
$statement->bindParam(':id', $id);
$statement->execute();
$statement = $db->prepare("INSERT INTO approved (fname, lname, student_id, email, type) (SELECT fname, lname, student_id, email, type FROM waiting WHERE id = :id)");
$statement->bindParam(':id', $id);
$statement->execute();

在我执行其他查询之前，我还尝试将$statement设置为null，但这也不起作用：

$statement = $db->prepare("UPDATE waiting SET wait = :status WHERE id = :id");
$statement->bindValue(':status', 0);
$statement->bindParam(':id', $id);
$statement->execute();
$statement = null;
$statement = $db->prepare("INSERT INTO approved (fname, lname, student_id, email, type) (SELECT fname, lname, student_id, email, type FROM waiting WHERE id = :id)");
$statement->bindParam(':id', $id);
$statement->execute();

为什么这不起作用？

Answer 1

您的插入查询在语法上是错误的。从select周围删除括号，它应该有效：

INSERT INTO approved (fname, lname, student_id, email, type)
SELECT fname, lname, student_id, email, type FROM waiting WHERE id = :id

PDO查询不起作用

1 个答案: