如何为以下情况创建循环？

Question

/html/body/table/tr[1]/td[2]
/html/body/table/tr[1]/td[4]

/html/body/table/tr[3]/td[2]
/html/body/table/tr[3]/td[4]

/html/body/table/tr[5]/td[2]
/html/body/table/tr[5]/td[4]

因此，tr []的索引是奇数，td []总是2或4。

Answer 1

for(int i = 1; i < bound; i += 2) {
    for(int j = 2; j <= 4; j += 2) {
        Console.WriteLine(
            String.Format("/html/body/table/tr[{0}]/td[{1}]", i, j)
        );
    }
    Console.WriteLine();
}

Answer 2

你可以做一些简单的事情

for(tr = 1; tr < maxodd+1; tr += 2;)
{
    //pseudoimplementation
    /html/bod/table/tr[tr]/td[2]
    /html/bod/table/tr[tr]/td[4]

}

Answer 3

最天真的案例：

for(int i = 1; i < 6; i += 2) {
    Console.WriteLine("html/body/table/tr[" + i + "]/td[2]");
    Console.WriteLine("html/body/table/tr[" + i + "]/td[4]");
}