Question

我想基于ViewPriority将表CustomerAgreementRole加入到AgreementRoleGroup中只有一行。示例：CustomerAgreementRole可以具有三行。我只想要ViewPriority最高的加入的行

AgreementId, AgreementRoleId 
1            1
1            2
1            3  

CustomerAgreementRole

 1. AgreementId
 2. AgreementRoleId

AgreementRoleGroup

 1. AgreementRoleId
 2. ViewPriority

当前查询：

select * from CustomerAgreementRole car 
join (select agreementRoleId, min(ViewPriority) as mi from AgreementRoleGroup group by AgreementRoleId) as arg on car.AgreementRoleId = arg.AgreementRoleId

预期结果：

AgreementId, AgreementRoleId, ViewPriority
1            1                1

Answer 1

可能是这样的：

git reset --hard develop

Answer 2

由于AgreementRoleGroup已获得AgreementRoleId，因此我们可以{% for kpi in csf.getKeyPerformanceIndicators%} ... {% endfor %}进行一些子查询

join

但是我会说使用select a.*, b2.ViewPriority from CustomerAgreementRole a left join ( select b.AgreementRoleId, b.ViewPriority from AgreementRoleGroup b where b.ViewPriority = ( select min(ViewPriority) from AgreementRoleGroup ) ) b2 on a.AgreementRoleId=b2.AgreementRoleId并不是最好的方法，您应该在@gotqn答案中使用min()，但现在可以使用。

重新编辑

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我将这些用作示例数据并获得了此结果documentation

如果您只希望一行而不在乎ViewPriority是否需要最小，请改用create table CustomerAgreementRole (AgreementId int,AgreementRoleId int); insert into CustomerAgreementRole values (1,1); insert into CustomerAgreementRole values (2,3); insert into CustomerAgreementRole values (3,4); insert into CustomerAgreementRole values (4,2); create table AgreementRoleGroup (AgreementRoleId int, ViewPriority int); insert into AgreementRoleGroup values (1,3); insert into AgreementRoleGroup values (3,4); insert into AgreementRoleGroup values (4,2); insert into AgreementRoleGroup values (2,1);

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Answer 3

对于每个AgreementId，您需要具有最高优先级（最低ViewPriority值）的AgreementRoleId。这意味着您要对CustomerAgreementRole行进行排名，并且仅显示排名最高的行。排名通常是通过SQL中的ROW_NUMBER，RANK或DENSE_RANK完成的。

select AgreementId, AgreementRoleId, ViewPriority
from
(
  select
    car.AgreementId, car.AgreementRoleId, arg.ViewPriority,
    row_number() over (partition by car.AgreementId order by arg.ViewPriority) as rn
  from CustomerAgreementRole car
  join AgreementRoleGroup arg on arg.AgreementRoleId = car.AgreementRoleId
) ranked
where rn = 1;

Answer 4

使其与此配合使用：

WITH CTEViewPriority (lowestViewPriority, agreementId) as (
    select min(ViewPriority), AgreementId from CustomerAgreementRole as car 
    left join AgreementRoleGroup arg on car.AgreementRoleId = arg.AgreementRoleId
    group by agreementId
    )
select * from CustomerAgreementRole as car
inner join CTEViewPriority as arg on lowestViewPriority = arg.agreementRoleId and arg.agreementId = car.agreementId

SQL连接仅1行

4 个答案: