Question

我打开一个文件，其中每一行代表一个学生的信息。像这样存储：

41097-xxkx:Johansson Elin:TE20:290

每个值都用":"分隔的地方。下一行是新学生，依此类推。

通过这个，我将把值添加到字典中，这样每个学生都会得到“ prsnummer”，“ namn”等字典。然后将这些字典存储在列表中。

# How I think about dealing with it.
# Tho stripping every part, and adding to dict was harder.

with open("text.txt", "r") as f:
    for line in f:
        """
        Do something
        """  

# How txt files look like. Each value is seperated with a :
# 040512-xxkx:Valek Kevin:TE20:280
# 041097-xxkx:Johansson Elin:TE20:290

# In the end it will look like:
list_of_dicts = [
{"prsnummer" : "040512-xxkx", "namn" : "Valek Kevin", "Klass" : "TE20", "Merit" : "280"},
{"prsnummer" : "041097-xxkx", "namn" : "Johansson Elin", "Klass" : "TE20", "Merit" : "290"}
]

# (Merit is meant to be stored as a str)

Answer 1

挺直的

list_of_dicts = []
with open("text.txt", "r") as f:
    curr_dict = {}
    for line in f:
        values = line.split(":") 
        curr_dict["prsnummer"] = values[0]
        curr_dict["namn"] = values[1]
        curr_dict["Klass"] = values[2]
        curr_dict["Merit"] = values[3]
    list_of_dicts.append(curr_dict)

基本上，您会分析行，将字符串拆分为“：”字符，然后根据列表位置提取信息

例如，在字符"040512-xxkx:Valek Kevin:TE20:280"上拆分字符串":"，将生成此values列表

values = line.split(":")
# ["040512-xxkx", "Valek Kevin", "TE20", "280"]

在位置0（值[0]）中，您具有字符串“ 040512-xxkx”
在位置1（值[1]）中，您具有字符串“ Valek Kevin”
在位置2（值[2]）中，您具有字符串“ TE20”
在位置2（值[3]）中，您具有字符串“ 280”

Answer 2

您需要在冒号上分割行，然后使用上面为每行列出的键来构建字典。

with open("text.txt", "r") as f:
    list_of_dicts = []
    keys = ["prsnummer", "namn", "Klass", "Merit"]
    for line in f:
        values = line.split(':')
        list_of_dicts.append(dict(zip(keys, values)))

从文本文件中读取值，然后将每个值添加到追加到列表的字典中

2 个答案: