我正在尝试根据到期时间(按货币分组)对特定列“ TENOR”进行排序-例如,应按以下顺序排序:ON,SW,1M,2M,3M,6M,9M,1Y ,18M,2Y等等。.其中ON =隔夜,SW =一周,1M = 1个月。我尝试按情况使用订单,但不确定我错过了什么,它总是在结果顶部提供18M。
答案 0 :(得分:1)
您可以使用ps -ef | grep php
(或DECODE
)语句(并可以放置有意义的值),并且由于要获取3个字符的子字符串,因此需要包括尾随空格:
如果您的查询的简化版本为:
CASE
对于测试数据:
SELECT SUBSTR( name, 9, 3 ) AS tenor,
name
FROM table_name
ORDER BY SUBSTR( name, 1, 8 ),
DECODE(
tenor,
'ON ', 1/30,
'SW ', 7/30,
'1M ', 1,
'2M ', 2,
'3M ', 3,
'6M ', 6,
'9M ', 9,
'1Y ', 12,
'18M', 18,
'2Y ', 24,
'3Y ', 36,
'5Y ', 60,
'10Y', 120,
NULL
) ASC NULLS LAST
这将输出:
TENOR | NAME :---- | :--------------------- 1M | ARZ USD 1M FX FORWARD 2M | ARZ USD 2M FX FORWARD 3M | ARZ USD 3M FX FORWARD 6M | ARZ USD 6M FX FORWARD 9M | ARZ USD 9M FX FORWARD 1Y | ARZ USD 1Y FX FORWARD 18M | ARZ USD 18M FX FORWARD 1M | BRZ USD 1M FX FORWARD 1Y | BRZ USD 1Y FX FORWARD 10Y | BRZ USD 10Y FX FORWARD
db <>提琴here
答案 1 :(得分:1)
您会尝试此代码吗? “ table1”是用于数据准备测试的CTE。通过将 regexp_substr 函数与模式'\ w +'一起使用,可以从文本中得到第三个单词,并得到'\ d +'第一位数字。然后,为了进行正确的排序,将数字乘以12,将年份转换成月份,并将默认值设置为“ ON” -1,“ SW” 1然后将其升序排序。
with table1("name")
as (
select 'ARZ USD 18M FX FORWARD' from dual union all
select 'ARZ USD 1M FX FORWARD' from dual union all
select 'ARZ USD 1Y FX FORWARD' from dual union all
select 'ARZ USD 2M FX FORWARD' from dual union all
select 'ARZ USD 3M FX FORWARD' from dual union all
select 'ARZ USD 6M FX FORWARD' from dual union all
select 'BRZ USD 10Y FX FORWARD' from dual union all
select 'BRZ USD 1M FX FORWARD' from dual union all
select 'BRZ USD 1Y FX FORWARD' from dual union all
select 'BRZ USD 2M FX FORWARD' from dual union all
select 'BRZ USD 2Y FX FORWARD' from dual union all
select 'BRZ USD 3M FX FORWARD' from dual union all
select 'BRZ USD 3Y FX FORWARD' from dual union all
select 'BRZ USD 5Y FX FORWARD' from dual union all
select 'BRZ USD 6M FX FORWARD' from dual union all
select 'BRZ USD 7Y FX FORWARD' from dual union all
select 'BRZ USD 9M FX FORWARD' from dual union all
select 'CLZ USD 1M FX FORWARD' from dual union all
select 'BRZ USD ON FX FORWARD' from dual union all
select 'BRZ USD SW FX FORWARD' from dual
)
select
regexp_substr("name",'\w+',1,3) as tenor,
-------------------
t.*
from table1 t
order by nvl(to_number(regexp_substr("name",'\d+',1,1)),1)*decode(substr(regexp_substr("name",'\w+',1,3),-1),'M',1,'Y', 12, 'N', -1, 'W', 0,-999) asc
;
结果如下
TENOR name
ON BRZ USD ON FX FORWARD
SW BRZ USD SW FX FORWARD
1M ARZ USD 1M FX FORWARD
1M CLZ USD 1M FX FORWARD
1M BRZ USD 1M FX FORWARD
2M BRZ USD 2M FX FORWARD
2M ARZ USD 2M FX FORWARD
3M BRZ USD 3M FX FORWARD
3M ARZ USD 3M FX FORWARD
6M BRZ USD 6M FX FORWARD
6M ARZ USD 6M FX FORWARD
9M BRZ USD 9M FX FORWARD
1Y BRZ USD 1Y FX FORWARD
1Y ARZ USD 1Y FX FORWARD
18M ARZ USD 18M FX FORWARD
2Y BRZ USD 2Y FX FORWARD
3Y BRZ USD 3Y FX FORWARD
5Y BRZ USD 5Y FX FORWARD
7Y BRZ USD 7Y FX FORWARD
10Y BRZ USD 10Y FX FORWARD
答案 2 :(得分:0)
您正在按name
进行排序,然后解码为tenor
。但是name
有一个标准前缀,后跟高阶值。因此,所有具有相同前缀的名称都将按男高音名称排序。
解决方案是按前缀和解码后的男高音进行排序:
order by trim(substr(name,1,8))
, case when tenor = ...
此外,用于提取男高音的代码还包含一个错误。您的子字符串长3个字符,但许多男高音只有2个字符:因此,您要提取带有后缀空格的'ON '
,但是在CASE语句中,您正在检查'ON'
,它与提取的不匹配子字符串。我建议您修剪提取的男高音:
rtrim(substr(name,9,3)) as tenor
我已经尝试了上述解决方案,但是在1M之前还有18M的情况
是的,这很有趣。我转载了它。我不确定为什么会发生这种情况,但已通过对substr()
进行修整来解决它。这是a working demo on db<>fiddle。