Question

我想从“ orders”表WHERE order_id = 2中获取数组数据，然后插入“ inventory_log”表中。但是我的代码只插入了最后一行

订单表

order_id  product_id  quantity 
     2          1            9
     2          3            2
     3          6            3
     3          5            2
     2          7            1

我想要这个：

inventory_log表格

    id  product_id      quantity 
     1          1            9
     2          3            2
     3          7            1

在下面找到我的代码：

<?php
define('DB_SERVER','localhost');
define('DB_USER','root');
define('DB_PASS' ,'');
define('DB_NAME', 'store');
$con = mysqli_connect(DB_SERVER,DB_USER,DB_PASS,DB_NAME);
// Check connection
if (mysqli_connect_errno())
{
 echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

// Insert into inventory_log TABLE
if(isset($_POST['Submit']))
  {
$productID=$_POST['product_id'];
$IssueQty=$_POST['quantity'];


$inventory=mysqli_query($con,"insert into inventory_log(productID, IssueQty) values('$productID', '$IssueQty')"); 

echo '<script>alert("Sucessful")</script>';
}
?>


<html>
  <head>
  <meta http-equiv="content-type" content="text/html; charset=utf-8">
  <title></title>
  </head>
  <body>
    <form method="post" name="submit">
    <table border="1">
     <thead>
        <tr>
        <th>Product ID</th>
        <th>Quantity</th>
        </tr>
    </thead>
    <tbody>
    <?php     
    // Get order items from orders TABLE
    $result = $con->query("SELECT order_id, product_id, quantity
    FROM orders
    WHERE order_id = 2"); 
    if($result->num_rows > 0){  
    while($item = $result->fetch_assoc()){ 
    $product_id = $item["product_id"];
    $quantity = $item["quantity"];  
    ?>
    <tr>
      <td><input type="text" name="product_id" value="<?php echo $product_id; ?>"></td> 
      <td><input type="text" name="quantity" value="<?php echo $quantity; ?>"></td>
    </tr>     
    <?php } } ?>
    </tbody>
    </table>
<button type="submit" name="Submit" class="btn btn-success btn-sm">Submit</button>
    <form>
  </body>
</html>

Answer 1

仅插入一行，因为您仅发布1个product_id和1个数量

您在php中发布的数据现在看起来像：

<td><input type="text" name="product[<?= htmlentities($product_id)?>][product_id]" value="<?= htmlentities($product_id); ?>"></td>    
<td><input type="text" name="product[<?= htmlentities($product_id)?>][quantity]" value="<?= htmlentities($quantity); ?>"></td>

如果要通过帖子发送整个列表，则需要在输入名称中使用数组语法。

类似

$_POST = [
    product => [
       1 => [
          'product_id' =>  1,
          'quantity' =>  9
       ]  ,
       2 => [
          'product_id' =>  2,
          'quantity' =>  19
       ]  ,  
       .....
    ]
]

在您的php脚本中，这将导致POST具有数组值

if( isset( $_POST['product'])) {
    foreach( $_POST['product'] as $product) {
        $productID=$product['product_id'];
        $IssueQty=$product['quantity'];


        // your sql insert here!. please use sql escaping on your user input!
    }
}

您可以使用foreach（）进行迭代

from scipy.optimize import rosen, differential_evolution
bounds = [(0, 5), (0, 5), (0, 5), (0, 5), (0, 5)]
result = differential_evolution(rosen, bounds, disp=False)
print(result.x, result.fun)
import matplotlib.pyplot as plt
x, f = zip(*result)
plt.plot(x, f)

但是。使用脚本，您可以继续插入已有的所有行。我不知道这是否只是try / example，但我假设您只想插入新行。现在，您如何设置其继续插入已经拥有的所有行（即使不删除旧行）

从一个表中获取数组数据并插入到另一个表中

1 个答案: