我想使加速度计的值平滑一点,因为一点点摇晃会导致画布振动。
我尝试添加一些延迟,但是并不能解决问题。
我该怎么做?
public BubblePage()
{
InitializeComponent();
Device.StartTimer(TimeSpan.FromSeconds(1f / 60), () =>
{
BubbleCenterCircle.InvalidateSurface();
return true;
});
}
void canvasView_BubbleCenterCircle(object sender, SKPaintSurfaceEventArgs e)
{
var surface = e.Surface;
var canvas = surface.Canvas;
canvas.Clear(SKColors.Transparent);
var width = e.Info.Width;
var height = e.Info.Height;
canvas.Translate(width / 2, height / 2);
canvas.Scale(width / 300f);
canvas.DrawLine(-60, 0, 60, 0, whiteLine);
canvas.DrawLine(0, -60, 0, 60, whiteLine);
canvas.DrawCircle(0, 0, 60f, blackPaint);
float x = (float)Math.Round(acceleration.X * RoundingValue, 1);
float y = (float)Math.Round(acceleration.Y * RoundingValue, 1);
canvas.DrawCircle(x, -y, 15f, whitePaint);
}
void Accelerometer_ReadingChanged(object sender, AccelerometerChangedEventArgs e)
{
acceleration = e.Reading.Acceleration;
}
Vector3 acceleration;
const float RoundingValue = 60f;
答案 0 :(得分:0)
您想要采样加速度以使其平滑的声音。在这种情况下,延迟它没有帮助,因为该事件仍会被调用。
如果您无法控制事件的触发频率,则可以执行以下操作:
DateTime _lastRead;
TimeSpan _sampleRate = TimeSpan.FromSeconds(1);
void Accelerometer_ReadingChanged(object sender, AccelerometerChangedEventArgs e)
{
var now = DateTime.Now;
if ((now - _lastRead) >= _sampleRate)
{
acceleration = e.Reading.Acceleration;
_lastRead = now;
}
}
除非最后一次读取与现在的差值等于或大于采样率,否则不会分配acceleration
值。
如果这不是您想要的,则需要更加明确地说明要实现的目标。